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- Wed Feb 08, 2017 5:09 am
- Forum: National Math Olympiad (BdMO)
- Topic: BDMO NATIONAL Junior 2013/04
- Replies: 4
- Views: 3108
Re: BDMO NATIONAL Junior 2013/04
I would like to add some corrections from "ahmedittihad" 's answer. According to question, $a = 2^k$ Where, $k$ is any odd natural number Now, $ a^{2012} + a^{2013} + ...... + a^{3012} $ = $ a^{2012} ( 1 + a + a^{2} +.........+ a^{1000} )$ = $ 2^{2012 k} ( 1 + 2^{k} + 2^{2 k} +.........+ 2^{1000 k} ...