Search found 181 matches
- Sun Jan 22, 2017 4:34 pm
- Forum: Divisional Math Olympiad
- Topic: Geometry
- Replies: 10
- Views: 7229
Re: Geometry
Take any $4$ points, you will get three intersection points. And how many ways can you take 4 points? Yes, in $ \binom {2013}{4}$ ways.
- Sun Jan 22, 2017 4:27 pm
- Forum: Social Lounge
- Topic: Chat thread
- Replies: 53
- Views: 79063
Re: Chat thread
Hello everyone. I'm Ittihad. My interest includes procrastination and more procrastination.
- Sun Jan 22, 2017 4:21 pm
- Forum: Junior Level
- Topic: BDMO 2013 QUE-9
- Replies: 5
- Views: 4641
Re: BDMO 2013 QUE-9
Your solution is correct. But please latex your posts. It's mandatoey in the BdMO forum.
- Sun Jan 22, 2017 4:18 pm
- Forum: Higher Secondary Level
- Topic: need a book
- Replies: 5
- Views: 8127
Re: need a book
As far as I know, UKMT books are not avaiilable online. It's better if you contact Aiyub Vai.
- Thu Jan 19, 2017 6:14 pm
- Forum: Algebra
- Topic: Seems ugly, But cute
- Replies: 5
- Views: 3917
Re: Seems ugly, But cute
His proof isn't much ugly. I'm more amazed at his patience of latexing.
- Tue Jan 17, 2017 11:43 pm
- Forum: Junior Level
- Topic: Rajshahi '15 \10
- Replies: 3
- Views: 3492
Re: Rajshahi '15 \10
Thanic Nur Samin, let us have some glory. As $ST$ is the perpendicular bisector, $\angle SPT=\angle SRT$. Which is also equal to $\angle QPS$. We get, $\triangle QPS$ is similar to $\triangle QRP$. From length chasing and the similar triangle, we get, $PQ= 9^(1/2)*16^(1/2)= 12$. We have, $ PS/PQ= PR...
- Sun Jan 15, 2017 6:04 pm
- Forum: Junior Level
- Topic: Regional '12 Junior Geometry
- Replies: 1
- Views: 2499
Re: Regional '12 Junior Geometry
There's certainly something wrong with this problem. I think there should be some mkre information about $OD$.
- Sun Jan 15, 2017 4:36 pm
- Forum: Algebra
- Topic: Seems ugly, But cute
- Replies: 5
- Views: 3917
Re: Seems ugly, But cute
Thamim really outdone himself this time.
- Sat Jan 14, 2017 9:08 pm
- Forum: Secondary Level
- Topic: 2015 regional secondary no. 2 probability
- Replies: 3
- Views: 3291
Re: 2015 regional secondary no. 2 probability
Erm, I'm getting a different result. The probability of $10$ passengers coming is $11/2^{11}$. The probability of $11$ passengers coming is $1/2^{11}$.
So the probability of everyone getting a seat would be $1- 11/2^{11} - 1/2^{11}=( 2^{11}-12)/2^{11}$. So the answer is $3$.
So the probability of everyone getting a seat would be $1- 11/2^{11} - 1/2^{11}=( 2^{11}-12)/2^{11}$. So the answer is $3$.
- Sat Jan 14, 2017 12:46 pm
- Forum: National Math Olympiad (BdMO)
- Topic: BdMO National 2008: Secondary
- Replies: 5
- Views: 3934
Re: BdMO National 2008: Secondary
Do we need calculus in Math Olympiads?!