Search found 65 matches
- Wed Jan 18, 2017 10:50 pm
- Forum: Junior Level
- Topic: Kushtia '15 \9
- Replies: 2
- Views: 2848
Kushtia '15 \9
$ABCD$ is a trapezium. Both $AB$ and $CD$ is perpendicular to $AD$. If $AB<CD$, $AD=8, BC = AB + CD$ ; then $AB \times CD=?$
- Tue Jan 17, 2017 11:38 pm
- Forum: Junior Level
- Topic: Rajshahi '15 \10
- Replies: 3
- Views: 3499
Re: Rajshahi '15 \10
My solution: Let $T'$ is a point on $PQ$ such that $PT' = PT$. Now,$\angle SPT = \angle SPT' , PT = PT' , PS = PS$ So,$\triangle PST \cong \triangle PST'$. So,$\angle QTS = 90$ degree. Because $\frac{QS}{SR} = \frac{9}{7}$.So $\frac{PQ}{PR} = \frac{9}{7}$. Thus, $PQ = 9q , PR = 7q , q$ is a real num...
- Tue Jan 17, 2017 11:10 pm
- Forum: Junior Level
- Topic: Rajshahi '15 \10
- Replies: 3
- Views: 3499
Rajshahi '15 \10
$PQR$ is a triangle.$SP$ is the angle bisector of $\angle QPR$ and $ST$ is the perpendicular bisector of $PR$.If $QS=9cm$ and $SR=7cm$ then $PR = \frac{x}{y}$ where $x, y$ are coprimes. $x +y = ?$
- Fri Jan 13, 2017 7:10 pm
- Forum: Secondary Level
- Topic: Dhaka regional 16 P4
- Replies: 5
- Views: 5034
Re: Dhaka regional 16 P4
Sorry!I missed some questions. How ${\angle}PQX = {\angle}PRZ$ and${\angle}PQR = {\angle}PXY$?
- Fri Jan 13, 2017 6:13 pm
- Forum: Secondary Level
- Topic: Dhaka regional 16 P4
- Replies: 5
- Views: 5034
Re: Dhaka regional 16 P4
How can you write $XZ = 2XY$?
- Sat Jan 07, 2017 5:32 pm
- Forum: Junior Level
- Topic: Regional '12 Junior Geometry
- Replies: 1
- Views: 2508
Regional '12 Junior Geometry
N.B.:I think this problem contains an error.$OD,OE$ can be infinitely long.
- Sat Jan 07, 2017 5:07 pm
- Forum: Junior Level
- Topic: Alien's Calculation
- Replies: 1
- Views: 2340
Re: Alien's Calculation
Solution : The problem statement assures that the aliens use $12$ based number system.So we can covert this in the way how we convert decimal to binary or octal or hexa and so on.First we can make a chart: Decimal -> Aliens($12$ based) $ 0 -> 0$ $ 1 -> 1$ $ 2 -> 2$ $ 3 -> 3$ $ 4 -> 4$ $ 5 -> a$ $ 6 ...
- Thu Jan 05, 2017 11:12 pm
- Forum: Junior Level
- Topic: BDMO 2016 6No
- Replies: 6
- Views: 4726
Re: BDMO 2016 6No
As the mobile card number contains $6$ digits , for every digit there will be three options. So the total number will be $3^6 = 729$.
- Wed Jan 04, 2017 11:24 pm
- Forum: Junior: Solved
- Topic: Dhaka Junior 2015/9
- Replies: 1
- Views: 8106
Re: Dhaka Junior 2015/9
this problem is already discussed in viewtopic.php?f=8&p=17163#p17163.Just a difference : $AB = 2$ instead of $1$.
- Fri Dec 30, 2016 11:33 am
- Forum: Junior Level
- Topic: BdMO '16 regional junior/9
- Replies: 3
- Views: 3668
BdMO '16 regional junior/9
Need help to solve this problem.