1&1nly

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sakibtanvir
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1&1nly

Unread post by sakibtanvir » Wed Feb 08, 2012 9:44 pm

Find all integers of four digits,Which has the following quality,\[abcd=a^b*c^d\]
Here, $a,b,c,d$ denotes the numbers of the integer and \[a\neq b\neq c\neq d\]
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nafistiham
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Re: 1&1nly

Unread post by nafistiham » Wed Feb 08, 2012 10:32 pm

\[a=b=c=d\]
\[abcd=a^4=(a^2)^2\]
\[a^b\cdot c^d=(a^a)^2\]
\[a^a=a^2\]
:lol:
\[\sum_{k=0}^{n-1}e^{\frac{2 \pi i k}{n}}=0\]
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sakibtanvir
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Re: 1&1nly

Unread post by sakibtanvir » Thu Feb 09, 2012 10:10 am

hey,How did you multiply a,b,c,d???????I told it is to just denote the numbers of the integer :x :x
An amount of certain opposition is a great help to a man.Kites rise against,not with,the wind.

Abdullah
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Re: 1&1nly

Unread post by Abdullah » Thu Feb 09, 2012 10:17 am

I think there is just one number which can be written in this form and this is,$2592=2^5*9^2$ :)

sakibtanvir
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Re: 1&1nly

Unread post by sakibtanvir » Thu Feb 09, 2012 10:19 am

Good job,Abdullah!!
An amount of certain opposition is a great help to a man.Kites rise against,not with,the wind.

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nafistiham
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Re: 1&1nly

Unread post by nafistiham » Thu Feb 09, 2012 1:47 pm

sakibtanvir wrote:hey,How did you multiply a,b,c,d???????I told it is to just denote the numbers of the integer :x :x
ohohoho! :oops: :oops:
got it wrong.
\[\sum_{k=0}^{n-1}e^{\frac{2 \pi i k}{n}}=0\]
Using $L^AT_EX$ and following the rules of the forum are very easy but really important, too.Please co-operate.
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Eesha
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Re: 1&1nly

Unread post by Eesha » Wed Feb 15, 2012 11:18 am

Abdullah wrote:I think there is just one number which can be written in this form and this is,$2592=2^5*9^2$ :)
কিন্তু আব্দুল্লাহ তোমার সমাধানে প্রবলেম আছে, এখানে তুমি $2$টা $2$ দিয়ে দিয়েছ। কিন্তু বলা আছে যে, \[a\neq b\neq c\neq d\]
গণিত অলেম্পিয়াডে প্রাইজ পাওয়াটাই আসল না। প্রাইজ সবসময় পায়না এমন অনেকেও অনেক ভাল।

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