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BdMO Online Forum • View topic - Find $$<x+<y$$

Find $$<x+<y$$

For students of class 6-8 (age 12 to 14)

Find $$<x+<y$$

here is the problem.......
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jayon

Posts: 20
Joined: Thu Dec 08, 2016 12:10 am

Re: Find $$<x+<y$$

( $360^{\circ}$ $-$ $x$ ) $+$ ( $360^{\circ}$ $-$ $y$ ) = $720^{\circ}$ $-$ ( $30^{\circ}$ $+$ $45^{\circ}$ $+$ $50^{\circ}$ $+$ $25^{\circ}$ )

$\Rightarrow$ $x$ $+$ $y$ = $150$
We cannot solve our problems with the same thinking we used when we create them.

Kazi_Zareer

Posts: 86
Joined: Thu Aug 20, 2015 7:11 pm
Location: Malibagh,Dhaka-1217

Re: Find $$<x+<y$$

Kazi_Zareer wrote:( $360^{\circ}$ $-$ $x$ ) $+$ ( $360^{\circ}$ $-$ $y$ ) = $720^{\circ}$ $-$ ( $30^{\circ}$ $+$ $45^{\circ}$ $+$ $50^{\circ}$ $+$ $25^{\circ}$ )

$\Rightarrow$ $x$ $+$ $y$ = $150$

how did you get that $720^{\circ}$ $-$ ( $30^{\circ}$ $+$ $45^{\circ}$ $+$ $50^{\circ}$ $+$ $25^{\circ}$ )??

jayon

Posts: 20
Joined: Thu Dec 08, 2016 12:10 am

Re: Find $$<x+<y$$

Use this formula: $(n-2) \times 180^{\circ}$ for measuring the sum of the internal angles of a regular $n$-gon. Now try to think about it.
We cannot solve our problems with the same thinking we used when we create them.

Kazi_Zareer

Posts: 86
Joined: Thu Aug 20, 2015 7:11 pm
Location: Malibagh,Dhaka-1217

Re: Find $$<x+<y$$

X+Y=150˚,as because by extending some lines in the figure,at a point;we find Y+30˚ as the supplementary angle of X ;so,X+Y+30=180˚,X+Y=150˚
aritra barua

Posts: 45
Joined: Sun Dec 11, 2016 2:01 pm