Find $$<x+<y$$
 Kazi_Zareer
 Posts: 86
 Joined: Thu Aug 20, 2015 7:11 pm
 Location: Malibagh,Dhaka1217
Re: Find $$<x+<y$$
( $360^{\circ}$ $$ $x$ ) $+$ ( $360^{\circ}$ $  $ $y$ ) = $720^{\circ}$ $ $ ( $ 30^{\circ}$ $+$ $45^{\circ}$ $+$ $50^{\circ}$ $+$ $25^{\circ}$ )
$ \Rightarrow $ $x$ $+$ $y$ = $150$
$ \Rightarrow $ $x$ $+$ $y$ = $150$
We cannot solve our problems with the same thinking we used when we create them.
Re: Find $$<x+<y$$
how did you get that $720^{\circ}$ $ $ ( $ 30^{\circ}$ $+$ $45^{\circ}$ $+$ $50^{\circ}$ $+$ $25^{\circ}$ )??Kazi_Zareer wrote:( $360^{\circ}$ $$ $x$ ) $+$ ( $360^{\circ}$ $  $ $y$ ) = $720^{\circ}$ $ $ ( $ 30^{\circ}$ $+$ $45^{\circ}$ $+$ $50^{\circ}$ $+$ $25^{\circ}$ )
$ \Rightarrow $ $x$ $+$ $y$ = $150$
 Kazi_Zareer
 Posts: 86
 Joined: Thu Aug 20, 2015 7:11 pm
 Location: Malibagh,Dhaka1217
Re: Find $$<x+<y$$
Use this formula: $(n2) \times 180^{\circ} $ for measuring the sum of the internal angles of a regular $n$gon. Now try to think about it.
We cannot solve our problems with the same thinking we used when we create them.

 Posts: 48
 Joined: Sun Dec 11, 2016 2:01 pm
Re: Find $$<x+<y$$
X+Y=150˚,as because by extending some lines in the figure,at a point;we find Y+30˚ as the supplementary angle of X ;so,X+Y+30=180˚,X+Y=150˚