Find $$<x+<y$$

For students of class 6-8 (age 12 to 14)
User avatar
jayon
Posts: 20
Joined: Thu Dec 08, 2016 12:10 am

Find $$<x+<y$$

Unread post by jayon » Sat Dec 17, 2016 4:49 pm

here is the problem.......
Attachments
Untitled7.png
Untitled7.png (23.96 KiB) Viewed 491 times

User avatar
Kazi_Zareer
Posts: 86
Joined: Thu Aug 20, 2015 7:11 pm
Location: Malibagh,Dhaka-1217

Re: Find $$<x+<y$$

Unread post by Kazi_Zareer » Sun Dec 18, 2016 12:54 am

( $360^{\circ}$ $-$ $x$ ) $+$ ( $360^{\circ}$ $ - $ $y$ ) = $720^{\circ}$ $ -$ ( $ 30^{\circ}$ $+$ $45^{\circ}$ $+$ $50^{\circ}$ $+$ $25^{\circ}$ )

$ \Rightarrow $ $x$ $+$ $y$ = $150$
We cannot solve our problems with the same thinking we used when we create them.

User avatar
jayon
Posts: 20
Joined: Thu Dec 08, 2016 12:10 am

Re: Find $$<x+<y$$

Unread post by jayon » Sun Dec 18, 2016 11:55 am

Kazi_Zareer wrote:( $360^{\circ}$ $-$ $x$ ) $+$ ( $360^{\circ}$ $ - $ $y$ ) = $720^{\circ}$ $ -$ ( $ 30^{\circ}$ $+$ $45^{\circ}$ $+$ $50^{\circ}$ $+$ $25^{\circ}$ )

$ \Rightarrow $ $x$ $+$ $y$ = $150$
how did you get that $720^{\circ}$ $ -$ ( $ 30^{\circ}$ $+$ $45^{\circ}$ $+$ $50^{\circ}$ $+$ $25^{\circ}$ )??

User avatar
Kazi_Zareer
Posts: 86
Joined: Thu Aug 20, 2015 7:11 pm
Location: Malibagh,Dhaka-1217

Re: Find $$<x+<y$$

Unread post by Kazi_Zareer » Sun Dec 18, 2016 1:15 pm

Use this formula: $(n-2) \times 180^{\circ} $ for measuring the sum of the internal angles of a regular $n$-gon. Now try to think about it.
We cannot solve our problems with the same thinking we used when we create them.

aritra barua
Posts: 48
Joined: Sun Dec 11, 2016 2:01 pm

Re: Find $$<x+<y$$

Unread post by aritra barua » Thu Jan 19, 2017 7:23 pm

X+Y=150˚,as because by extending some lines in the figure,at a point;we find Y+30˚ as the supplementary angle of X ;so,X+Y+30=180˚,X+Y=150˚ :D

Post Reply