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Find $$<x+<y$$
Posted: Sat Dec 17, 2016 4:49 pm
by jayon
here is the problem.......
Re: Find $$<x+<y$$
Posted: Sun Dec 18, 2016 12:54 am
by Kazi_Zareer
( $360^{\circ}$ $-$ $x$ ) $+$ ( $360^{\circ}$ $ - $ $y$ ) = $720^{\circ}$ $ -$ ( $ 30^{\circ}$ $+$ $45^{\circ}$ $+$ $50^{\circ}$ $+$ $25^{\circ}$ )
$ \Rightarrow $ $x$ $+$ $y$ = $150$
Re: Find $$<x+<y$$
Posted: Sun Dec 18, 2016 11:55 am
by jayon
Kazi_Zareer wrote:( $360^{\circ}$ $-$ $x$ ) $+$ ( $360^{\circ}$ $ - $ $y$ ) = $720^{\circ}$ $ -$ ( $ 30^{\circ}$ $+$ $45^{\circ}$ $+$ $50^{\circ}$ $+$ $25^{\circ}$ )
$ \Rightarrow $ $x$ $+$ $y$ = $150$
how did you get that $720^{\circ}$ $ -$ ( $ 30^{\circ}$ $+$ $45^{\circ}$ $+$ $50^{\circ}$ $+$ $25^{\circ}$ )??
Re: Find $$<x+<y$$
Posted: Sun Dec 18, 2016 1:15 pm
by Kazi_Zareer
Use this formula: $(n-2) \times 180^{\circ} $ for measuring the sum of the internal angles of a regular $n$-gon. Now try to think about it.
Re: Find $$<x+<y$$
Posted: Thu Jan 19, 2017 7:23 pm
by aritra barua
X+Y=150˚,as because by extending some lines in the figure,at a point;we find Y+30˚ as the supplementary angle of X ;so,X+Y+30=180˚,X+Y=150˚
