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BdMO Online Forum • View topic - BDMO 2016 6No

BDMO 2016 6No

For students of class 6-8 (age 12 to 14)
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BDMO 2016 6No

Post Number:#1  Unread postby siwomcre » Thu Jan 05, 2017 10:43 pm

A mobile company uses only the digits 0, 1 and 2 to make their mobile cards. If
the mobile cards are of 6 digits, then how many cards can they supply to the
market?

Plz can anyone give the solution?
Explanation of the solution would help much :D
siwomcre
 
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Re: BDMO 2016 6No

Post Number:#2  Unread postby Absur Khan Siam » Thu Jan 05, 2017 11:12 pm

As the mobile card number contains $6$ digits , for every digit there will be three options. So the total number will be $3^6 = 729$.
"(To Ptolemy I) There is no 'royal road' to geometry." - Euclid
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Re: BDMO 2016 6No

Post Number:#3  Unread postby SMMamun » Fri Jan 06, 2017 3:43 am

Imagine there are exactly 6 (blank) circles drawn on each mobile card, and exactly one digit is printed inside each circle to make a particular card number. In how many ways can you fill the 1st circle, the 2nd circle, and so on?
SMMamun
 
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Re: BDMO 2016 6No

Post Number:#4  Unread postby siwomcre » Fri Jan 06, 2017 11:53 am

SMMamun wrote:Imagine there are exactly 6 (blank) circles drawn on each mobile card, and exactly one digit is printed inside each circle to make a particular card number. In how many ways can you fill the 1st circle, the 2nd circle, and so on?

60466176
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Re: BDMO 2016 6No

Post Number:#5  Unread postby SMMamun » Fri Jan 06, 2017 4:05 pm

@ siwomcre, what is the result if you can use only the digits 0, 1 and 2 (NOT ALL of 0 – 9) in the circles?
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Re: BDMO 2016 6No

Post Number:#6  Unread postby siwomcre » Fri Jan 06, 2017 4:11 pm

SMMamun wrote:@ siwomcre, what is the result if you can use only the digits 0, 1 and 2 (NOT ALL of 0 – 9) in the circles?

in each circle i can fill up any of the 3 digits 0,1,2
Then it would 729
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Re: BDMO 2016 6No

Post Number:#7  Unread postby aritra barua » Wed Jan 18, 2017 9:55 pm

We may consider a 6 digit number abcdef and place each of the numbers in the respective positions.In that case,we may find that the number of 6 digit numbers are 2*3*3*3*3*3 as we cannot place 0 in the position a.So there are 486 cards,we can make
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