problem from gonit ishkul -2

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nafistiham
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problem from gonit ishkul -2

Unread post by nafistiham » Wed Dec 07, 2011 7:00 pm

in $ABDC$ quadrangle, diagonal $AB$ bisects $\angle CBD$ $DB$ and $DA$ touches the circumcentre of $ABC$ at $A$ and $B$. if the circumcentre of $ABC$ is $20$ and $ABD$ is $12$. find $BD$
\[\sum_{k=0}^{n-1}e^{\frac{2 \pi i k}{n}}=0\]
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Labib
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Re: problem from gonit ishkul -2

Unread post by Labib » Wed Dec 07, 2011 9:17 pm

এইগুলা কি লিখস??? ঠিক কর...
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Re: problem from gonit ishkul -2

Unread post by nafistiham » Wed Dec 07, 2011 11:12 pm

আচ্ছা,বাংলায় কপি করতিছি ।
$ADBC$ চতুর্ভুজে $AB$ কর্ণ $\angle CBD$ কোণকে সমদিখন্দিত করে । $DB$ এবং $DA$ বাহুদ্বয় $ABC$ ত্রিভুজের পরিবৃত্তকে $A$ এবং $B$ বিন্দুতে স্পর্শ করে । $ABC$ ও $ABD$ ত্রিভুজের পরিসীমা যথাক্রমে $২০$ ও $১২$ । $BD$ এর দৈর্ঘ্য কত ?
\[\sum_{k=0}^{n-1}e^{\frac{2 \pi i k}{n}}=0\]
Using $L^AT_EX$ and following the rules of the forum are very easy but really important, too.Please co-operate.
Introduction:
Nafis Tiham
CSE Dept. SUST -HSC 14'
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nafistiham@gmail

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Labib
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Re: problem from gonit ishkul -2

Unread post by Labib » Wed Dec 07, 2011 11:31 pm

You have written 'Circumcentre' instead of 'Perimeter' I think.
There is no integer solution for $BD$. I think the solution is
$3<BD<3.5$
.
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Labib
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Re: problem from gonit ishkul -2

Unread post by Labib » Wed Dec 07, 2011 11:37 pm

Hints::
Notice that, $\angle DBA=\angle DAB=\angle ACB=\angle ABC$.
Thus, in $\triangle ABC, AB=AC$ and in $\triangle ABD, AD=BD$.
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Ipsc palash
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Re: problem from gonit ishkul -2

Unread post by Ipsc palash » Sat Dec 10, 2011 11:32 pm

MAY BE (40/6)=6.6'

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Re: problem from gonit ishkul -2

Unread post by Ipsc palash » Sun Dec 11, 2011 1:06 am

MY ANSWER IS ABSULATELY WRONG.কিভাবে বের করব

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Labib
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Re: problem from gonit ishkul -2

Unread post by Labib » Sun Dec 11, 2011 2:39 pm

Why dont you try the hints... Palash.
Please Install $L^AT_EX$ fonts in your PC for better looking equations,
Learn how to write equations, and don't forget to read Forum Guide and Rules.


"When you have eliminated the impossible, whatever remains, however improbable, must be the truth." - Sherlock Holmes

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