Angles and Midpoints
- Thanic Nur Samin
- Posts:176
- Joined:Sun Dec 01, 2013 11:02 am
Let $B$ and $C$ be two points and $M$ be their midpoint. Let $X$ be also a point on the same plane. Define $T$ to be a point so that $\angle XMT=90^{\circ}$ and $XB=XT$ which lies inside the circumcircle of $BMX$. Prove that, $\angle TXB=2\angle MTC$.
Hammer with tact.
Because destroying everything mindlessly isn't cool enough.
Because destroying everything mindlessly isn't cool enough.
- Thanic Nur Samin
- Posts:176
- Joined:Sun Dec 01, 2013 11:02 am
Re: Angles and Midpoints
Hammer with tact.
Because destroying everything mindlessly isn't cool enough.
Because destroying everything mindlessly isn't cool enough.