let $ABCDE$ be a convex pentagon such that
$\angle BAC =\angle CAD =\angle DAE$ and $\angle ABC =\angle ACD =\angle ADE$.
Diagonals $BD$ and $CE$ meet at $P$. Prove that ray $AP$ bisects $CD$.
ISL 2006 G3
The study of mathematics, like the Nile, begins in minuteness but ends in magnificence.
- Charles Caleb Colton
- Charles Caleb Colton
Re: ISL 2006 G3
My solution
The study of mathematics, like the Nile, begins in minuteness but ends in magnificence.
- Charles Caleb Colton
- Charles Caleb Colton
- Atonu Roy Chowdhury
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Re: ISL 2006 G3
Solution with spiral similarity is easy. Here I'm gonna give a different solu. And I chased some angles and lengths.
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