Infinite solutions
Posted: Tue Jul 04, 2017 7:46 pm
Find with proof every pair of ($a$,$b$) in general form such that $a+b^2$|$a^3+b^3$.
$-a \equiv b^2 (moda+b^2) $.
So, $-a^3 \equiv b^6 (moda+b^2) $.
Which implies that $a+b^2 | b^6-b^3$.
Now fix $b$ and notice that for every divisor $x $ of $b^6-b^3$ there exists a $a $ such that $a+b^2=x $. So we get infinite solutions.