BdMO Online Forum

Posted: **Tue Feb 01, 2011 11:24 pm**

i know but i'm working on the rest

Posted: **Sat Feb 05, 2011 3:03 am**

There is a problem,$4ab-1,$not $2ab-1$

Posted: **Sun Feb 06, 2011 3:02 am**

$$2ab-1$$ hbe......oitato IMO-07 ER MATH

Posted: **Sun Feb 27, 2011 12:53 pm**

Hasib wrote:$4a^2-1$ is odd number, so $(4a^2-1)^2$ is odd number. It gives 2 divides an odd number. Impossible. no solution for $(a,b)$

Obviously false argument since there was $2ab-1,$odd not $2ab,$ even
And what Moon meant is here:

find (a,b)