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rakeen wrote:You can't plug 3 or 4 or 5 in the series since the series is for $-1<x<=1$ only
Then write a function exp(x) to calculate (e^x) and use binary search.
rakeen wrote:you mean... if logx=p then $e^p=x$. then trial and error?!
However mahi's method worked
rakeen wrote:Then write a function exp(x) to calculate (e^x) and use binary search.
you mean... if logx=p then $e^p=x$. then trial and error?!
However mahi's method worked
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