Geometry
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Please don't post problems (by starting a topic) in the "X: Solved" forums. Those forums are only for showcasing the problems for the convenience of the users. You can always post the problems in the main Divisional Math Olympiad forum. Later we shall move that topic with proper formatting, and post in the resource section.
Four points P,Q,R and S are taken from the circumference of the circle in anticlockwise direction such that QR>PQ and SP>RS. The bisector oof <PQR and <RSP intersect the circle at point M and N respectively. In the cyclic hexagon drawn by the points P, Q, R, S, M, N four sides are equal to each other. If PM=5, then SQ= ?
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Re: Geometry
Rid1 wrote: ↑Sat Aug 26, 2017 8:59 pmFour points $P,Q,R ,S$ are taken from the circumference of the circle in anticlockwise direction such that $QR>PQ$ and $SP>RS$. The bisector of $\angle{PQR}$ and $\angle{RSP}$ intersect the circle at point $M$ and $N$ respectively. In the cyclic hexagon drawn by the points $P, Q, R, S, M, N$ four sides are equal to each other. If $PM=5$, then $SQ=$ ?