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Mymensingh higher secondary 2013#9

Posted: Mon Feb 18, 2019 12:46 am
by samiul_samin
For a function $f:R\rightarrow R,f(xy+1)=f(x)f(y)-f(y)-x+2$ and $f(0)=1$
$f(2013)+f(2012)=$?

Re: Mymensingh higher secondary 2013#9

Posted: Mon Feb 18, 2019 8:52 am
by samiul_samin
Hint
Put $x=y=1$
Answer
$4027$