## Search found 138 matches

Sun Mar 02, 2014 5:11 pm
Forum: Geometry
Topic: Triangle Inside a Square
Replies: 1
Views: 1593

$ABCD$ is a square where $AB=4.$ $P$ is a point inside the square such that $\angle PAB = \angle PBA = 15^\circ.$ $E$ and $F$ are the midpoints of $AD$ and $BC$ respectively. $EF$ intersects $PD$ and $PC$ at points $M$ and $N$ respectively. $Q$ is a point inside the quadrilateral $MNCD$ such that $\... Sat Feb 08, 2014 6:56 pm Forum: National Math Olympiad (BdMO) Topic: BdMO National 2012: Junior 5 Replies: 5 Views: 3314 ### Re: BdMO National 2012: Junior 5 I could solve the 1st part only....can anyone explain the another one..... Brother please show your ans of 1st part :| 1st part ACB%2030.jpg In equilateral triangle$\triangle DEF$,$\angle DFE = \angle DEF = \angle EDF = 60^\circ\angle DFE =\angle CFG = 60^\circ\angle ACB = 90^\circ - \angle...
Tue Oct 15, 2013 12:43 pm
Forum: Computer Science
Topic: Font Size in C
Replies: 2
Views: 4515

### Font Size in C

How can I change font size in C ?
Wed Aug 28, 2013 8:36 pm
Forum: Junior Level
Topic: Italian MO 2002#P1
Replies: 5
Views: 2698

### Re: Italian MO 2002#P1

$34 \times (a+b+c) = 100a+10b+c$
$\Rightarrow 66a-24b-33c = 0$
$\Rightarrow 11 \times (2a-c) = 8b$

$8b$ will be divisible by $11$ if $b=0$.

Now, $11 \times (2a-c)=0$
$\Rightarrow 2a = c$

So the numbers are $102,204,306,408$.
Sat Aug 10, 2013 2:26 pm
Forum: Computer Science
Topic: Count The Number Of Solutions
Replies: 2
Views: 5215

### Count The Number Of Solutions

Suppose, I want to find the number of solutions of this equation $a+b+c+d=7$ ; where $a,b,c,d$ are natural numbers. To find the solutions I wrote the following code. #include <stdio.h> int main () { int a,b,c,d,n; for(a=1;a>=0 && a<=7;a++) {for(b=1;b>=0 && b<=7;b++) {for(c=1;c>=0 && c<=7;c++) {for(d...
Sat Aug 10, 2013 12:41 am
Forum: Algebra
Topic: algebra
Replies: 3
Views: 1993

### Re: algebra

When $x=1$ and $y=1$ , $z+t=5$ has $4$ solutions. Keeping $x=1$ fixed, $+1$ the value of $y$ gradually. Then $z+t$ will have $3,2$ and $1$ solutions for $y=2,3,4$ respectively. So keeping $x=1$ fixed, we get $4+3+2+1=10$ solutions. Keeping $x=2$ fixed, we get $(10-4)=6$ solutions. [4 solutions out. ...
Tue Mar 05, 2013 12:08 am
Forum: Social Lounge
Topic: APMO
Replies: 2
Views: 2519

### APMO

Today I saw an add on APMO. Will someone tell me in detail about it?
Mon Feb 25, 2013 4:46 pm
Forum: Number Theory
Topic: Perfect Square
Replies: 6
Views: 2427

### Re: Perfect Square

One more thing I want to say-
It can have more solutions except those 3.
Mon Feb 25, 2013 4:42 pm
Forum: Number Theory
Topic: Perfect Square
Replies: 6
Views: 2427