Search found 3 matches
- Thu Jan 06, 2011 2:02 pm
- Forum: Geometry
- Topic: Turkey 2000-2
- Replies: 4
- Views: 3723
Re: Turkey 2000-2
As $SP=SQ$ , $BA$ is the diameter, so by symmetry we get arc $PB=$ arc $BQ$ so, $\angle BQP$ $=$ $\angle BXQ$ But, $\angle DXB$ $=$180-$\angle PXB$ = $\angle BQP$ So. $BX$ is the internal angle bisector of $\angle DXC$ hence,$\frac{CB}{BD} $ = $\frac{CX}{XD}$ again.arc$PA$=arc$QA$ .so, $\angle PXA$ ...
- Fri Dec 17, 2010 2:38 pm
- Forum: Higher Secondary Level
- Topic: Two subset with equal sum
- Replies: 2
- Views: 3439
Re: Two subset with equal sum
forgot to write......Two set with same sum can have common elements.If they do,substract the sum of common elements from both sets and there will be two disjoint sets with same sum.If they don't,then the case is solved:):)
- Thu Dec 16, 2010 2:21 pm
- Forum: Higher Secondary Level
- Topic: Two subset with equal sum
- Replies: 2
- Views: 3439
Re: Two subset with equal sum
The highest sum of a subset here is 945(=90+91+92+93+94+95+96+97+98+99)
So the sum ranges from 1 to 945.
the number of subset is 1023(=2^10-1)
1023 subsets,945 sums,pigeonhole,..........................thats it \m/
So the sum ranges from 1 to 945.
the number of subset is 1023(=2^10-1)
1023 subsets,945 sums,pigeonhole,..........................thats it \m/