Search found 1 match
- Mon Apr 10, 2017 9:21 pm
- Forum: Junior Level
- Topic: Beginner's Marathon
- Replies: 68
- Views: 44853
Re: Beginner's Marathon
Mod note: This solution was for a wrong version of problem 12, asking for sum of $f(n)$ where $n=2^k$ only. The correct solution is below. Solution of Problem #12: $f(1) = f(2^0) = 0,\quad f(2) = f(2^1) = 1,\quad f(4) = f(2^2) = 2$, in this way, as all $n$ of $f(n)$ are the powers of $2$, so $f(2^k...