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- Mon Feb 05, 2018 8:53 pm
- Forum: National Math Olympiad (BdMO)
- Topic: BDMO 2017 National round Secondary 5
- Replies: 15
- Views: 11409
Re: BDMO 2017 National round Secondary 5
A synthetic solution : We denote the inscribed circle as $\omega$ , & $P,Q$ be the tangent point of arc $BC$ & $AB$ resp with $\omega$. We get, $AB=AC=r$ (radii of same circle) & $AB=BC$ similarly. $\Longrightarrow AB=AC=BC \Longrightarrow \triangle ABC$ is equilateral $\Longrightarrow \angle B =60...