Search found 17 matches
- Sat Mar 10, 2018 10:43 pm
- Forum: Higher Secondary Level
- Topic: Geometry
- Replies: 1
- Views: 5307
Re: Geometry
What is the source?
- Sat Mar 10, 2018 10:25 pm
- Forum: Higher Secondary Level
- Topic: probability
- Replies: 3
- Views: 7865
Re: probability
mathlomaniac wrote: [/tfrac{8}{8C3}]
- Fri Mar 09, 2018 5:49 pm
- Forum: Higher Secondary Level
- Topic: A problem of combinatorics
- Replies: 9
- Views: 20918
Re: A problem of combinatorics
36×35/2 =630
- Thu Mar 08, 2018 10:36 pm
- Forum: Secondary Level
- Topic: Boxes and Cards Problem
- Replies: 2
- Views: 4814
Re: Boxes and Cards Problem
Answer Box No. $ 3$ Solution Note that $2015=2016-1=(12×168)-1$, So,2015 is in form $12k-1$ where $k=1,2,3,...$ We are placing cards in the boxes in such a manner that every 12th card will be plced at the same box....($1$) Now,We have to put card no.$11$ in the $3$ rd box(According to the statement...
- Thu Mar 08, 2018 10:34 pm
- Forum: Secondary Level
- Topic: Greatest Positive Integer $x$
- Replies: 7
- Views: 8828
Re: Greatest Positive Integer $x$
Greatest possible integer value of X can be 88783 because 23 is repeated 88789 times in 2000!
- Thu Mar 08, 2018 8:37 pm
- Forum: Higher Secondary Level
- Topic: Rightmost two digits of 3^999
- Replies: 5
- Views: 8868
Re: Rightmost two digits of 3^999
27 is correct answer.
- Thu Mar 08, 2018 2:34 pm
- Forum: Secondary Level
- Topic: Greatest Positive Integer $x$
- Replies: 7
- Views: 8828
Re: Greatest Positive Integer $x$
Total times 23 and its multiple appear in 2000! Is 5213
Therefore maximum value of X would be 5213-6=5207
Therefore maximum value of X would be 5213-6=5207