Search found 22 matches

by math_hunter
Fri Mar 15, 2019 7:47 pm
Forum: National Math Olympiad (BdMO)
Topic: BdMO National Higher Secondary 2019/7
Replies: 3
Views: 7331

Re: BdMO National Higher Secondary 2019/7

Have you got the solution of this problem???
by math_hunter
Fri Mar 15, 2019 7:45 pm
Forum: National Math Olympiad (BdMO)
Topic: BdMO National Junior 2019/6
Replies: 4
Views: 54221

Re: BdMO National Junior 2019/6

I don't understand the solution.
How the area of APQD is (3/4)ADB, PBCS is (3/4)ABC, CSR is (1/4)ACD, DQR is (1/4)DBC???
Can you please narrate the solution?
by math_hunter
Fri Mar 15, 2019 7:11 pm
Forum: National Math Olympiad (BdMO)
Topic: BdMO National Primary 2019#5
Replies: 2
Views: 7034

Re: BdMO National Primary 2019#5

It's a very easy problem.
The answer is 17.
by math_hunter
Thu Mar 14, 2019 7:04 pm
Forum: Junior Level
Topic: BDMO 2016 Regional
Replies: 17
Views: 94134

Re: BDMO 2016 Regional

No need to get because I've already solve it
The answer is 112.
by math_hunter
Mon Mar 11, 2019 11:48 pm
Forum: Junior Level
Topic: BDMO 2016 Regional
Replies: 17
Views: 94134

Re: BDMO 2016 Regional

Ok...it's not a fact. Please try to give me the solution when you get it...
by math_hunter
Mon Mar 11, 2019 11:47 pm
Forum: Junior Level
Topic: BDMO 2016 Regional
Replies: 17
Views: 94134

Re: BDMO 2016 Regional

Why are you not eager to prove this??? This is a very interesting problem.
by math_hunter
Mon Mar 11, 2019 11:40 pm
Forum: Junior Level
Topic: BDMO 2016 Regional
Replies: 17
Views: 94134

Re: BDMO 2016 Regional

No...no...this isn't the standard of math. You need to prove it.
by math_hunter
Mon Mar 11, 2019 11:37 pm
Forum: Junior Level
Topic: BDMO 2016 Regional
Replies: 17
Views: 94134

Re: BDMO 2016 Regional

How do you get those angle's value?
by math_hunter
Mon Mar 11, 2019 11:28 pm
Forum: Junior Level
Topic: BDMO 2016 Regional
Replies: 17
Views: 94134

Re: BDMO 2016 Regional

Once upon a time,I tried a lot to solve this problem but didn't find the answer.I think this is not a very tough problem. If you connect the centers you will get a rhombus with angles $100,100,80,80$ Than $\tan\theta=\tan {40}=\dfrac {42}{X}\Rightarrow X=50\Rightarrow 2X=\fbox {100}$(about) Here, $...