Search found 2 matches
- Tue Feb 08, 2011 5:23 pm
- Forum: National Math Olympiad (BdMO)
- Topic: BdMO National Higher Secondary 2007/7
- Replies: 6
- Views: 7477
Re: BdMO National Higher Secondary 2007/7
I am quite sure that the solution is the following: f(x)= 1+x+x^2+x^3+.....+x^6 Now if we write it like this: f(x)= 1+x+x^2+x^3+.....infinite, then f(x)= (1-x)^(-1) f(x^7)=(1-x^7)^(-1) so f(x^7)/f(x) = (1-x)/(1-x^7) according to remainder theorem, the remainder is = 0 so Answer: 0. (Osman, a friend ...
- Tue Feb 08, 2011 1:02 pm
- Forum: National Math Olympiad (BdMO)
- Topic: BdMO National Higher Secondary 2007/2
- Replies: 2
- Views: 2965
Re: BdMO National Higher Secondary 2007/2
If I am not wrong, then the solution is:
Between triangle XOY and OYZ, XO=OY=OZ=5 (radius of the same circle) and <XOY=<OYZ=60 degree.
So, triangle XOY =~ OYZ. So, XY=OZ=5.
Between triangle XOY and OYZ, XO=OY=OZ=5 (radius of the same circle) and <XOY=<OYZ=60 degree.
So, triangle XOY =~ OYZ. So, XY=OZ=5.