Search found 15 matches
- Tue Mar 30, 2021 4:37 pm
- Forum: Higher Secondary Level
- Topic: An Algebraic Problem
- Replies: 6
- Views: 7395
Re: An Algebraic Problem
ভাই, এই অঙ্কটা যে বেসিক ও দক্ষতা দরকার পড়েছে৷ সেগুলো কীভাবে অর্জন করেছেন, একটু গাইডলাইন দিলে উপকৃত হতাম খুব। অনেক অনেক ধন্যবাদ।
- Tue Mar 30, 2021 10:01 am
- Forum: Higher Secondary Level
- Topic: An Algebraic Problem
- Replies: 6
- Views: 7395
- Mon Mar 29, 2021 9:21 pm
- Forum: Higher Secondary Level
- Topic: An Algebraic Problem
- Replies: 6
- Views: 7395
An Algebraic Problem
If $a, b, c$ are natural numbers so that $\left(1 + \dfrac{1}{a}\right)\left(1 + \dfrac{1}{b}\right)\left(1 + \dfrac{1}{c}\right) = 2$, then figure out all the possible values of $a, b$ and $c$.
- Fri Mar 26, 2021 10:04 pm
- Forum: Higher Secondary Level
- Topic: Mymensingh Regional 2017 P4
- Replies: 2
- Views: 5579
Re: Mymensingh Regional 2017 P4
Thank you so much. It 's seeming very easy to me after you solved the problem. Thanks bhai.
- Fri Mar 26, 2021 6:09 pm
- Forum: Higher Secondary Level
- Topic: Mymensingh Regional 2017 P4
- Replies: 2
- Views: 5579
Mymensingh Regional 2017 P4
Using the six digits 1,3,5,6,7,9 once at a time how many 6 digit numbers can be built which are divisible by 11?
- Thu Mar 25, 2021 2:47 am
- Forum: Higher Secondary Level
- Topic: BdMO 2020 Regional Higher Secondary
- Replies: 2
- Views: 5652
BdMO 2020 Regional Higher Secondary
You have 4 different two digit numbers. Among them, product of any 3 is a full square number. What can be the lowest number among these 4 numbers?
- Tue Mar 23, 2021 2:20 pm
- Forum: Higher Secondary Level
- Topic: BdMO 2020 Higher Secondary Regional P9
- Replies: 3
- Views: 5977
BdMO 2020 Higher Secondary Regional P9
f(n)=f(n-1)+2n-2 and f(1)=2 then what is the value of f(100) ?
- Mon Mar 22, 2021 2:56 am
- Forum: Higher Secondary Level
- Topic: BdMO 2020 Regional Higher Secondary P1
- Replies: 6
- Views: 6931
Re: BdMO 2020 Regional Higher Secondary P1
That's an amazing solution. I also solved the problem but used a long naive area based solution. Thank you very much, learned a new way to think.Anindya Biswas wrote: ↑Sun Mar 21, 2021 3:46 pmWe know that area of a triangle= base×height/2
So, $2\times\triangle ABC=CF\cdot AB=BE\cdot AC$
$\therefore \frac{CF}{BE}=\frac{AC}{AB}=2$
- Sun Mar 21, 2021 1:41 pm
- Forum: Higher Secondary Level
- Topic: BdMO 2020 Regional Higher Secondary P1
- Replies: 6
- Views: 6931
BdMO 2020 Regional Higher Secondary P1
In a triangle ABC, AB=30, BC=50 and AC=60. Length of CF = k × Length of BE. Find k?
- Wed Mar 17, 2021 12:26 am
- Forum: Higher Secondary Level
- Topic: BdMO 2020 Regional Higher Secondary P8
- Replies: 1
- Views: 5160
BdMO 2020 Regional Higher Secondary P8
f f(x)=3x-2, then what is the value of x in the following equation? x=f(f(f(...f(x)...))) [2020 times]