The answer will be: 10!-{(1+2+3+4+5+6+7+8)*9}=3628800-36*9=3628476
PROOF:
if we take three person x,y,z
then,x can obtain position 1,2
y can obtain position 1,2,3
z can obtain position 1,2,3
so,in this case the sequence number is 3!-(1*2)=6-2=4
in the same way , this answer is 3628476
Search found 2 matches
- Mon Mar 15, 2021 11:34 am
- Forum: National Math Olympiad (BdMO)
- Topic: BdMO National Junior 2020 P4
- Replies: 10
- Views: 7533
- Mon Mar 15, 2021 10:39 am
- Forum: National Math Olympiad (BdMO)
- Topic: BdMO National Higher Secondary 2020 P8
- Replies: 8
- Views: 9630
Re: BdMO National Higher Secondary 2020 P8
I think that is 14.If we take n=3,then numbers are 1,2,3 then , the kayayi sequences are 1,3,2 2,1,3 3,1,2 Again if we take n=4,then the numbers are 1,2,3,4 Then the sequences are ; 1,2,4,3 2,1,3,4 3,1,2,4 4,1,2,3 we can see that every time the kayayi sequece number is equal to n . that is why , if ...