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- Thu Mar 25, 2021 5:18 pm
- Forum: Higher Secondary Level
- Topic: BdMO 2020 Higher Secondary Regional P9
- Replies: 3
- Views: 5702
Re: BdMO 2020 Higher Secondary Regional P9
This solution kinda gets messy for generalizing it. But bear with me. $f(100)=f(1)+2(1+2+3+\cdots +98+99)$ $f(100)=2+2(\frac{99\times 98}{2})$ $f(100)=2+2(4851)$ $\therefore f(100)=9704$ Just a little correction :) $f(100)=f(1)+2(1+2+3+\cdots +98+99)$ $f(100)=2+2(\frac{99\times 100}{2})$ $f(100)=2+...