Search found 4 matches
- Tue Jun 22, 2021 11:33 am
- Forum: National Math Camp
- Topic: Special Problem Marathon
- Replies: 38
- Views: 33019
Re: Special Problem Marathon
Injective ar surjective gulay felsi
- Tue Jun 22, 2021 9:52 am
- Forum: National Math Camp
- Topic: Special Problem Marathon
- Replies: 38
- Views: 33019
Re: Special Problem Marathon
$\textbf{Problem 17:}$ Assume real numbers $a_i,b_i\,(i=0,1,\cdots,2n)$ satisfy the following conditions: (1) for $i=0,1,\cdots,2n-1$, we have $a_i+a_{i+1}\geq 0$; (2) for $j=0,1,\cdots,n-1$, we have $a_{2j+1}\leq 0$; (2) for any integer $p,q$, $0\leq p\leq q\leq n$, we have $\sum_{k=2p}^{2q}b_k>0$....
- Mon Jun 21, 2021 8:28 pm
- Forum: Number Theory
- Topic: a question of primitive root
- Replies: 2
- Views: 5852
Re: a question of primitive root
yeah.
consider p=29 , r=31.
that'll do the work
consider p=29 , r=31.
that'll do the work
- Mon Jun 21, 2021 4:56 pm
- Forum: National Math Camp
- Topic: Special Problem Marathon
- Replies: 38
- Views: 33019
Re: Special Problem Marathon
We claim f(a)=s for all a belongs to Z.where s is an integer Clearly for the function f(a)=s for all $a$ belongs to Z, f+g function is surjective where g is subjective. For the sake of contradiction , we consider f(a) $\neq s $ for some a. So eventually we must get some b for which f(b)-f(b+1) $\neq...