## Search found 92 matches

- Wed Feb 01, 2012 12:00 am
- Forum: International Mathematical Olympiad (IMO)
- Topic: IMO(1995-1) Collinearity Of AM, DN and XY
- Replies:
**2** - Views:
**1311**

### Re: IMO(1995-1) Collinearity Of AM, DN and XY

my solution might be wrong, if it is, i request people to correct it: I have denoted the point $O$ as $P$ here. Sorry for the inconvinience. Let $T$ be the intersection of $AM$ and $XY$(extended). Now $TQ$ is the perpendicualr to $AD$.$Q$ is the foot of perpendicular from $T$ to $AD$. Now, $\angle T...

- Sat Jan 21, 2012 11:19 am
- Forum: National Math Olympiad (BdMO)
- Topic: BdMO 2010 higher secondary Q. 6
- Replies:
**7** - Views:
**2633**

### Re: BdMO 2010 higher secondary Q. 6

@Nadim,

$a \ne b$ if this condition is maintained, then the ans will be $2.(804)^2 + 401.400$.

$a \ne b$ if this condition is maintained, then the ans will be $2.(804)^2 + 401.400$.

- Sat Jan 21, 2012 10:36 am
- Forum: National Math Olympiad (BdMO)
- Topic: BdMO National Higher Secondary 2010/5
- Replies:
**3** - Views:
**1481**

### Re: BdMO National Higher Secondary 2010/5

I second Nadim ul abrar, I think the answer should be 14.

@Labib.

2010 has 16 divisors out of which there will be no polygons with side 1 or 2, So i think the answer is 14.

@Labib.

2010 has 16 divisors out of which there will be no polygons with side 1 or 2, So i think the answer is 14.

- Sat Jan 14, 2012 9:56 pm
- Forum: National Math Olympiad (BdMO)
- Topic: BdMO National Higher Secondary 2008/10
- Replies:
**2** - Views:
**1327**

### Re: BdMO National Higher Secondary 2008/10

Hints anyone?

- Sat Jan 14, 2012 9:56 pm
- Forum: National Math Olympiad (BdMO)
- Topic: BdMO National Higher Secondary 2008/9
- Replies:
**4** - Views:
**1890**

### Re: BdMO National Higher Secondary 2008/9

Hints anyone?

- Sat Jan 14, 2012 2:00 pm
- Forum: National Math Olympiad (BdMO)
- Topic: BdMO National Higher Secondary 2009/6
- Replies:
**6** - Views:
**2527**

### Re: BdMO National Higher Secondary 2009/6

@Labib Rashid: Could you explain your solution again? @Rafi, How did u get 1520?? Well,maybe I am wrong but here is my solution: From 40 movers, 3 movers can be chosen in $\binom{40}{3}$ ways. Now, let us count the number of ways that 3 movers can be selected such that there are no movers who sat ne...

- Sat Jan 14, 2012 1:11 pm
- Forum: National Math Olympiad (BdMO)
- Topic: BdMO National Higher Secondary 2008/4
- Replies:
**5** - Views:
**1721**

### Re: BdMO National Higher Secondary 2008/4

Tahmid, Tumi ki doye korso bolba??

- Sat Jan 14, 2012 10:42 am
- Forum: National Math Olympiad (BdMO)
- Topic: BdMO National Higher Secondary 2008/8
- Replies:
**2** - Views:
**1281**

### Re: BdMO National Higher Secondary 2008/8

Is the answer

$18.2$?

$18.2$?

- Sat Jan 14, 2012 10:05 am
- Forum: National Math Olympiad (BdMO)
- Topic: BdMO National Higher Secondary 2008/4
- Replies:
**5** - Views:
**1721**

### Re: BdMO National Higher Secondary 2008/4

TIHAM,

Hint:
Answer:

Hint:

- Wed Jan 11, 2012 4:42 pm
- Forum: National Math Olympiad (BdMO)
- Topic: BdMO National Higher Secondary 2007/11
- Replies:
**2** - Views:
**1218**

### Re: BdMO National Higher Secondary 2007/11

I did it like this. \[2cosx\leq|\sqrt{1+sin2x}-\sqrt{1-sin2x}|\] by squaring and simplifying 1. \[ 2cos^2x\le 1-cos2x\] 2. \[\Rightarrow 2cos^2x\le2-2cosx\] 3.\[\Rightarrow (cosx+1)(2cosx-1)\le0\] is there any bug :?: Tiham, I did not understand how u got from line 1 to line 2. $cos2x=2cos^2x-1$ Pu...