## Search found 155 matches

Tue Dec 30, 2014 9:40 pm
Forum: Higher Secondary Level
Topic: Looking for projective geometry books
Replies: 6
Views: 2869

### Re: Looking for projective geometry books

I'm going to mention and give some links to Projective Geometry books and pdf's. (Since, the idea of pole-polars are used the most in olympiad problems, I'll give some links seperately about that as well.) I hope others will continue the thread. $$ Projective Geometry , by, H.S.M. Coxeter $$ A...
Fri Dec 19, 2014 12:29 am
Forum: Geometry
Topic: Side, Angle, and, (Ex)-Circle
Replies: 4
Views: 1216

### Side, Angle, and, (Ex)-Circle

In $\triangle ABC$, $\angle A=2\angle C$. $(O)$ is its $A-$excircle, and, $M$ is the mid-point of $AC$. $OM\cap BC=D$. Show that,
$$ $AD$ bisects $\angle OAC$
$$ $BA=BD$
Sat Nov 29, 2014 8:20 pm
Forum: Geometry
Topic: powers are equal
Replies: 3
Views: 1018

### Re: powers are equal

$A,B,C$ all lie on the circles they are meant to be respected to. Not true. First, prove that, $AB',$ etc. are tangent to $\odot B'PC,$ etc. Then, the powers of $A, B,$ and $C$ w.r.t. the given circles are equal to the squares of $AB', BC', CA'$. So, we'll be done if we can show $AB'=BC'=CA'$. Now...
Tue Nov 11, 2014 7:53 pm
Forum: Junior Level
Topic: A confusion
Replies: 2
Views: 1177

### Re: A confusion

No, this isn't true...
Wed Oct 29, 2014 9:51 pm
Forum: Secondary Level
Topic: Floor sum
Replies: 1
Views: 877

Let, $S=\sum^{n}_{k=1}\lfloor\sqrt k\rfloor$. For all $1\leq k\leq (a^2-1)$, $\lfloor\sqrt k\rfloor=i$, where, $1\leq i\leq (a-1)$, $i\in \mathbb{N}$, and, $i$ appears exactly $(i+1)^2-i^2=(2i+1)$ times in $S$. $\therefore \sum^{a^2-1}_{k=1}\lfloor\sqrt k\rfloor=\sum_{i=1}^{a-1}i(2i+1)=2\sum i^2+\s... Sun Oct 26, 2014 8:48 pm Forum: Secondary Level Topic: A circle through incenter Replies: 2 Views: 1170 ### Re: A circle through incenter Clarification please... I think there's something wrong with the question Wed Oct 22, 2014 12:19 am Forum: Algebra Topic: (Angle)^(Side)[Inequality] Replies: 7 Views: 1898 ### Re: (Angle)^(Side)[Inequality] Oops... sorry I miscalculated by taking \frac{1}{x} instead of \frac{1}{\sin x} while differentiating... Tue Oct 21, 2014 12:04 am Forum: Algebra Topic: (Angle)^(Side)[Inequality] Replies: 7 Views: 1898 ### Re: (Angle)^(Side)[Inequality] \[f(x)=\frac{1}{\sin{x}}\cdot\ln\left(\frac{2x}{\pi}\right)$
Mon Oct 20, 2014 8:26 pm
Forum: Algebra
Topic: (Angle)^(Side)[Inequality]
Replies: 7
Views: 1898

### Re: (Angle)^(Side)[Inequality]

I think one Jensen can suffice... Sun Oct 19, 2014 10:42 pm
Forum: Algebra
Topic: (Angle)^(Side)[Inequality]
Replies: 7
Views: 1898

### (Angle)^(Side)[Inequality]

Let, $ABC$ be a triangle with angles $A,B,C$, and, sides $a,b,c$ (usual notations). Let, $R$ be the circum-radius. Prove that, $\left(\frac{2A}{\pi}\right)^\frac{1}{a}\left(\frac{2B}{\pi}\right)^\frac{1}{b}\left(\frac{2C}{\pi}\right)^\frac{1}{c}\leq \left(\frac{2}{3}\right)^{\frac{\sqrt{3}}{R}}$