Search found 110 matches

by Tahmid
Wed Aug 28, 2013 11:32 pm
Forum: National Math Camp
Topic: [OGC1] Online Geometry Camp: Day 4
Replies: 32
Views: 14572

Re: [OGC1] Online Geometry Camp: Day 4

solution of problem 4: first let the centre of the circle is O. now, $\angle EBF+\angle GCF=180$ $\therefore \frac{1}{2}\angle EBF+\frac{1}{2}\angle GCF=90$ or,$\angle OBF+\angle OCF=90$ or,$\angle BOC=90$ samely we get $\angle BOC=\angle AOD=90$ now let GC=FC=x and GD=HD=y. use pythagorus's theorem...
by Tahmid
Wed Aug 28, 2013 7:04 pm
Forum: National Math Camp
Topic: [OGC1] Online Geometry Camp: Day 4
Replies: 32
Views: 14572

Re: [OGC1] Online Geometry Camp: Day 4

solution of problem 3: let the intersecting point of AD and BE is G. that means G is the centroid of $\Delta ABC$. so,AG=2GD and BG=2GE; now , $AG^{2}+GE^{2}=AE^{2}$ or, $AG^{2}+GE^{2}=(\frac{AC}{2})^{2}$ or, $(2GD)^{2}+GE^{2}=(69.5)^{2}$ or, $4GD^{2}+GE^{2}=4830.25$.....1st result and $BG^{2}+GD^{2...
by Tahmid
Wed Aug 28, 2013 5:34 pm
Forum: Geometry
Topic: two circles
Replies: 3
Views: 1383

Re: two circles

ohhhh :shock: ...i have mitake a line. asif is right. D is the midpoint of AB.
by Tahmid
Wed Aug 28, 2013 12:59 pm
Forum: Geometry
Topic: two circles
Replies: 3
Views: 1383

two circles

plz give me the solve of this problem..... $\omega_1$ and $ \omega_2$ are two concentric circles where $\omega_1> \omega_2$. A tangent of $\omega_ 2$ at point $B$ touches $\omega_ 1$ at points $A$ and $C$. $D$ is the midpoint of $AB$. Another line through point $A$ touches $\omega_ 2$ at points $E$ ...
by Tahmid
Mon Aug 26, 2013 10:51 pm
Forum: National Math Camp
Topic: [OGC1] Online Geometry Camp: Day 2
Replies: 22
Views: 10748

Re: [OGC1] Online Geometry Camp: Day 2

I have also solved the problem by using stewart's theorem like Samiun Fateeha Ira and i also unable to see any bangla text .... :?
by Tahmid
Mon Aug 26, 2013 9:04 am
Forum: National Math Camp
Topic: [OGC1] Online Geometry Camp: Day 1
Replies: 19
Views: 10564

Re: [OGC1] Online Geometry Camp: Day 1

$\Delta APQ$ is isoscles and $\angle PAQ$=42. so $\angle PAQ=\angle AQP$=(180-42)/2=69. now compare for $\Delta BDQ$, x+y=$\angle BQA$=$\angle PQA$=$\angle AQP$=69.....1st result and compare for $\Delta BRP$, y+z=180-$\angle BPR$=180-$\angle APQ$=180-69=111....2nd result now multiply 1st and 2nd res...
by Tahmid
Sat Aug 24, 2013 7:46 pm
Forum: News / Announcements
Topic: Online Geometry Camp 2014 Phase 1
Replies: 19
Views: 8658

Re: Online Geometry Camp 2014 Phase 1

নায়েল ভাইয়ার e-mail adress জানতে চাই...???
by Tahmid
Sat Aug 24, 2013 6:19 pm
Forum: News / Announcements
Topic: Online Geometry Camp 2014 Phase 1
Replies: 19
Views: 8658

Re: Online Geometry Camp 2014 Phase 1

কুরিয়ার করে পাঠানোর ঠিকানা জানতে চাই। আর উন্মুক্ত আলোচনার কোন সময়ে হবে?......নাকি যেকোন সময়?
by Tahmid
Fri Mar 22, 2013 8:53 pm
Forum: Geometry
Topic: Medians and Side Lengths
Replies: 2
Views: 1140

Medians and Side Lengths

pls give me the solution of this problem:
Find the ratio of the area of a given tringle to that of a tringle whose sides have the same lengths as the medians of the original triangle.
by Tahmid
Thu Mar 21, 2013 3:05 pm
Forum: Introductions
Topic: camp info
Replies: 5
Views: 3398

camp info

I am new in this forum.....help me......pls inform me the problem of Kaykobad sir