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by ahmedittihad
Mon Mar 28, 2016 6:58 pm
Forum: Number Theory
Topic: International Zhautykov Olympiad 2005, Problem 6
Replies: 2
Views: 1785

Re: International Zhautykov Olympiad 2005, Problem 6

$pq$ divides $p^2q^2 +8(p^2 +q^2)+64$
so, $pq$ divides $8(p^2 +q^2 +8)$
so, $p$ divides $q^2$ and $q$ divides $p^2$