$pq$ divides $p^2q^2 +8(p^2 +q^2)+64$
so, $pq$ divides $8(p^2 +q^2 +8)$
so, $p$ divides $q^2$ and $q$ divides $p^2$
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- Mon Mar 28, 2016 6:58 pm
- Forum: Number Theory
- Topic: International Zhautykov Olympiad 2005, Problem 6
- Replies: 2
- Views: 3168