Search found 38 matches

Fri Apr 26, 2019 4:35 pm
Forum: Physics
Topic: BdPhO Regional (Dhaka-South) Higher Secondary 2019/1
Replies: 0
Views: 38261

BdPhO Regional (Dhaka-South) Higher Secondary 2019/1

BdPhO Regional (Dhaka-South) Higher Secondary 2019(1).png A coherent beam of monochromatic light of wavelength \$500\$ \$nm\$ is directed towards two thin slits separated by a distance of \$1\$ \$mm\$. If the screen covers an angular region of \$60˚\$, as shown in the figure, approximately how many bright in...
Thu Apr 25, 2019 9:33 pm
Topic: BdMO National Problem Collection(2011-2018)
Replies: 3
Views: 7293

Re: BdMO National Problem Collection(2011-2018)

Thank you very much. That'll be really very useful for us.
Thu Apr 25, 2019 9:24 pm
Forum: Physics
Topic: BdPhO Regional (Dhaka-South) Secondary 2019/6
Replies: 1
Views: 8316

Re: BdPhO Regional (Dhaka-South) Secondary 2019/6

Given, \$n(y)=ky,\$ \$where\$ \$0<y<h\$. Suppose that, \$y_1<y_2<y_3\$. Then, \$n_1<n_2<n_3\$, Hence, \$sin θ_1>sinθ_2>sinθ_3\$ (Snell's law) \$⇒\$ \$θ_1>θ_2>θ_3\$ BdPhO Regional (Dhaka-South) Secondary 2019(6S).png By Snell's law, \$\dfrac{n_1}{n_2}=\dfrac{sinθ_2}{sinθ_1}\$ \$∴\$ \$n_1 sinθ_1=n_2 sinθ_2=n_3 sinθ_3=...=...
Thu Apr 25, 2019 8:19 pm
Topic: BdMO National Secondary 2018:Full Solution
Replies: 2
Views: 14466

Re: BdMO National Secondary 2018:Full Solution

samiul_samin wrote:
Mon Feb 25, 2019 1:45 pm
All solution of the problems of BdMO National Secondary \$2018\$ are available here.

How did you know about that?
Wed Apr 24, 2019 8:29 pm
Forum: Physics
Topic: BdPhO Regional (Dhaka-South) Secondary 2019/7
Replies: 1
Views: 8312

Re: BdPhO Regional (Dhaka-South) Secondary 2019/7

Let the point where the water slide touches the ground be \$D\$. At point \$D\$, \$v_0^2=2gH\$. At point \$B\$, \$v^2=v_0^2-2gh=2g(H-h)\$. Now, Azmain should travel on PROJECTILE MOTION .(If you have no idea about projectile motion, you can click on the link for easy explanation.) Velocity among \$X\$ axis, \$v_...
Wed Apr 24, 2019 5:29 pm
Forum: Physics
Topic: BdPhO Regional (Dhaka-South) Secondary 2019/4
Replies: 1
Views: 8226

Re: BdPhO Regional (Dhaka-South) Secondary 2019/4

As the system is isolated, energy cannot enter or get out from it. The ball is released from height, \$H\$. When it touches the ground, the kinetic energy converts into sound and thermal energy. I mean, \$Kinetic\$ \$Energy\$ \$=\$ \$Sound\$ \$Energy\$ \$+\$ \$Thermal\$ \$Energy\$ But in fact, the sound energy is neg...
Wed Apr 24, 2019 4:59 pm
Forum: Secondary Level
Topic: 0^0=1!
Replies: 1
Views: 6703

0^0=1!

Yeah, that's not any joke! I'm really gonna prove that!
We know, \$2^6=64\$
Again, \$2^6=(2+0)^6=6_{C_0}2^60^0+6_{C_1}2^50^1+6_{C_2}2^40^2+...=64*0^0\$ \$⇒64=64*0^0\$
Which is a clear proof of \$0^0=1\$.
True to say, I haven't found any mistake here.
Wed Apr 24, 2019 4:57 pm
Forum: Algebra
Topic: 0^0=1!
Replies: 5
Views: 41272

0^0=1!

Yeah, that's not any joke! I'm really gonna prove that!
We know, \$2^6=64\$
Again, \$2^6=(2+0)^6=6_{C_0}2^60^0+6_{C_1}2^50^1+6_{C_2}2^40^2+...=64*0^0\$ \$⇒64=64*0^0\$
Which is a clear proof of \$0^0=1\$.
True to say, I haven't found any mistake here.
Wed Apr 24, 2019 1:44 pm
Forum: Physics
Topic: BdPhO Regional (Dhaka-South) Secondary 2019/1
Replies: 1
Views: 8276

Re: BdPhO Regional (Dhaka-South) Secondary 2019/1

Firstly let's make the picture easy. BdPhO Regional (Dhaka-South) Secondary 2019(1S).png Here, \$R_1=2 Ω, R_2=3 Ω, R_3=1 Ω, R_4=4 Ω, R_5=5 Ω\$ Current cannot flow throw voltmeter, so \$R_5\$ is useless. Equivalent Resistance, \$R=\dfrac{(R_1+R_2)(R_3+R_4)}{R_1+R_2+R_3+R_4}=2.5Ω\$ \$∴\$ \$I=\dfrac{V}{R}=4\$ \$A...
Wed Apr 24, 2019 12:43 pm
Forum: Social Lounge
Topic: Share your AoPS id name
Replies: 5
Views: 23561

Re: Sharing my AoPS id name

My AoPS ID is SINAN_EXPERT.