Can any1 give me links for some projective geometry books and articles?
*Projective geometry by HSM Coxeter is specially preferred
Search found 25 matches
- Mon Dec 29, 2014 6:40 pm
- Forum: Higher Secondary Level
- Topic: Looking for projective geometry books
- Replies: 7
- Views: 15488
- Fri Sep 20, 2013 7:28 pm
- Forum: Junior Level
- Topic: সহজ, কিন্তু সহজ নয়
- Replies: 4
- Views: 4697
Re: সহজ, কিন্তু সহজ নয়
গত ৬ সেপ্টেম্বর অনুষ্ঠিত হয় ৬ষ্ঠ দিনাজপুর গণিত উৎসব । নিচে দেয়া সমস্যাটি এসেছিল সেকেন্ডারি গ্রুপে। মনে হয় পারসি, কিন্তু ভাল কোন লজিক পাচ্ছি না। :roll: :roll: :roll: :roll: :roll: । সাহায্য কর। সমস্যাঃ একটি গুণোত্তর ধারার প্রথম পদ 1। ৫ম পদ a^4 এবং ৫ম পদ পর্যন্ত সমষ্টি 0। (১) a এর বাস্তব মান আছে? ...
- Fri Sep 20, 2013 6:57 pm
- Forum: Secondary Level
- Topic: Help 2 prove (Combi.)
- Replies: 3
- Views: 4094
Re: Help 2 prove (Combi.)
Wow, that was easy... & intelligent,too! However, I came up with a twisted critical proof today . Plz suggest me some effective books on Combinatorics(other than the 3 in the last camp) that cover some advanced topics.
- Thu Sep 19, 2013 3:36 pm
- Forum: Secondary Level
- Topic: Help 2 prove (Combi.)
- Replies: 3
- Views: 4094
Help 2 prove (Combi.)
$\sum_{k=0}^{a}\binom{a}{k}\binom{b}{k}=\binom{a+b}{a}=\binom{a+b}{b}$ when a\leq b.
For equality, $\sum_{k=0}^{a}\binom{a}{k}^{2}=\binom{2a}{a}$
How do u prove it?
For equality, $\sum_{k=0}^{a}\binom{a}{k}^{2}=\binom{2a}{a}$
How do u prove it?
- Thu Sep 19, 2013 3:17 pm
- Forum: Secondary Level
- Topic: Prime Range
- Replies: 2
- Views: 2720
Re: Prime Range
Well, u got a simpler proof... Didn't know about Bertrand's Postulate earlier... I was thinking to work out with Goldbach's Weak Conjecture instead...
- Sat Sep 14, 2013 11:51 pm
- Forum: Secondary Level
- Topic: Prime Range
- Replies: 2
- Views: 2720
Prime Range
Prove that any prime number is less than thrice the previous prime number
- Thu Feb 28, 2013 2:35 pm
- Forum: Secondary Level
- Topic: Congruence
- Replies: 10
- Views: 8267
Re: Congruence
If $4a+3b \equiv 1 \pmod{5}$ and $b \equiv 2 \pmod{3}$, $3a+b \equiv ? \pmod{5}$ (the least positive residue/reminder) The solution is much more simple than the given one: $4a+3b \equiv 1 \pmod{5} \Rightarrow 12a+9b \equiv 3 \pmod{5}$** $\Rightarrow 12a+4b \equiv 3 \equiv 8 \pmod{5} \Rightarrow 3a+...
- Thu Feb 28, 2013 1:43 pm
- Forum: Secondary Level
- Topic: Solve it
- Replies: 4
- Views: 3940
Solve it
If $(p-1)! \equiv -1 \text{ or } 0 \pmod{p}$ is false,
Find the values of $p$
Find the values of $p$
- Wed Feb 27, 2013 11:33 pm
- Forum: Secondary Level
- Topic: Help with Combinatorics
- Replies: 4
- Views: 3973
Re: Help with Combinatorics
Thanks for your help.
- Sun Feb 24, 2013 5:53 pm
- Forum: Secondary Level
- Topic: Help with Combinatorics
- Replies: 4
- Views: 3973
Re: Help with Combinatorics
I found it in "Combinatorics" by Marcusnayel wrote:This is not a common mathematical phrase. What is the context of its usage?