Search found 169 matches
- Fri Feb 04, 2011 11:42 pm
- Forum: H. Secondary: Solved
- Topic: Rangpur Higher Secondary 2011/3
- Replies: 6
- Views: 10962
Re: Rangpur Higher Secondary 2011/3
i got that later. My mistake! Sowry
- Fri Feb 04, 2011 12:05 am
- Forum: Social Lounge
- Topic: suggestion please...
- Replies: 6
- Views: 4403
Re: suggestion please...
thank u...
- Thu Feb 03, 2011 6:42 pm
- Forum: H. Secondary: Solved
- Topic: Rangpur Higher Secondary 2011/7
- Replies: 14
- Views: 19168
Re: Rangpur Higher Secondary 2011/7
sorry to argue.. Sorry
- Thu Feb 03, 2011 6:41 pm
- Forum: Secondary: Solved
- Topic: Rangpur Secondary 2011/6
- Replies: 7
- Views: 5510
Re: Rangpur Secondary 2011/6
sorry. Mistake
- Thu Feb 03, 2011 11:36 am
- Forum: Secondary: Solved
- Topic: Rangpur Secondary 2011/6
- Replies: 7
- Views: 5510
Re: Rangpur Secondary 2011/6
no..actually it is if $N=15x$ [$x=1,2] and divisible by 7 then quotient is twice the remainder.
- Thu Feb 03, 2011 11:09 am
- Forum: H. Secondary: Solved
- Topic: Rangpur Higher Secondary 2011/7
- Replies: 14
- Views: 19168
Re: Rangpur Higher Secondary 2011/7
i told to substract all the equation.
- Thu Feb 03, 2011 2:02 am
- Forum: H. Secondary: Solved
- Topic: Rangpur Higher Secondary 2011/3
- Replies: 6
- Views: 10962
Re: Rangpur Higher Secondary 2011/3
$-3<f<1$ and $-2<g<4$
if $f=-2.90$ and $g=-1.90$ their multiple $fg$ will give a positive answer!!!
thats why $6<fg<4$
if $f=-2.90$ and $g=-1.90$ their multiple $fg$ will give a positive answer!!!
thats why $6<fg<4$
- Thu Feb 03, 2011 1:55 am
- Forum: H. Secondary: Solved
- Topic: Rangpur Higher Secondary 2011/7
- Replies: 14
- Views: 19168
Re: Rangpur Higher Secondary 2011/7
the Left side of Equation is $A-z$ ok? So the right side is $1-2-3-4. . . . . . .-25-26$ =$1-(2+3+4+5. . . .+25+26)$ =$1-(1+2+3+4. . . .+25+26)+1$ =$2-(27*13)$ =$2-351$ =$-349$ ... There are 26 equations. When we substract 26 equation at a time the first and last variables will left on the left side...
- Thu Feb 03, 2011 1:20 am
- Forum: H. Secondary: Solved
- Topic: Rangpur Higher Secondary 2011/7
- Replies: 14
- Views: 19168
Re: Rangpur Higher Secondary 2011/7
u misunderstood (may be)[\B]Mehfuj Zahir wrote:Your formula is uncorrect.(A+B)-(B+C)=A-C
A-C+C-D=A-D
(A-D)+(D+E)=A-E
A-E+E+F=A+F
DO IT CONSECUTIVELY AND GET THE ANS -13
thats a sequence from A to Z.
- Wed Feb 02, 2011 11:48 pm
- Forum: H. Secondary: Solved
- Topic: Dhaka Higher Secondary 2010/10 (Secondary 2010/11)
- Replies: 6
- Views: 11328
Re: Dhaka Higher Secondary 2010/10 (Secondary 2010/11)
this question came many times.... I had it when i was class 9/10(2007/2008)