Search found 441 matches
- Sun Dec 11, 2011 2:12 pm
- Forum: Higher Secondary Level
- Topic: Prove me wrong
- Replies: 95
- Views: 55788
Re: Prove me wrong
There is nothing messy about it. Mathematics is a very precise science. it does not work just by saying things, no matter who says it. Look at the definitions again: Multiplicative inverse: The multiplicative inverse of a number x is a number y such that xy=1. Usually the inverse is written $x^{-1}$...
- Sun Dec 11, 2011 1:39 pm
- Forum: Higher Secondary Level
- Topic: Prove me wrong
- Replies: 95
- Views: 55788
Re: Prove me wrong
Look at the definition of division again, and prove how $0/0$ is defined. You cannot just make up random ideas and claim that to be a definition. If you could, then flying cows would be real because you can define flying cows as flying cows.
- Sun Dec 11, 2011 1:36 pm
- Forum: Higher Secondary Level
- Topic: Prove me wrong
- Replies: 95
- Views: 55788
Re: Prove me wrong
That's not a definition. That's nonsense.
- Sun Dec 11, 2011 2:36 am
- Forum: Higher Secondary Level
- Topic: Prove me wrong
- Replies: 95
- Views: 55788
Re: Prove me wrong
What is the definition of $0/0$?Abdul Muntakim Rafi wrote: $0/0=indeterminate$ ...
- Sat Dec 10, 2011 12:14 pm
- Forum: Higher Secondary Level
- Topic: Prove me wrong
- Replies: 95
- Views: 55788
Re: Prove me wrong
Look at the definition. Is it possible for $0$ to have a multiplicative inverse?
- Sat Dec 10, 2011 11:36 am
- Forum: Higher Secondary Level
- Topic: Prove me wrong
- Replies: 95
- Views: 55788
Re: Prove me wrong
We usually write the multiplicative inverse of $x$ as $1/x$.
You process is wrong because you first write $a/b$ which actually means $a \times \frac{1}{b}$. Now you cannot take $b=0$ because there is no such thing as $1/0$.
You process is wrong because you first write $a/b$ which actually means $a \times \frac{1}{b}$. Now you cannot take $b=0$ because there is no such thing as $1/0$.
- Sat Dec 10, 2011 11:33 am
- Forum: Higher Secondary Level
- Topic: Prove me wrong
- Replies: 95
- Views: 55788
Re: Prove me wrong
Lets start from definitions. Multiplicative inverse: The multiplicative inverse of a number $x$ is a number $y$ such that $xy=1$. Division: The division of a number $x$ by a number $y$ is $xy^{-1}$ where $y^{-1}$ is the multiplicative inverse of $y$. So you see dividing by $0$ is not defined because...
- Sat Dec 10, 2011 11:28 am
- Forum: Higher Secondary Level
- Topic: Prove me wrong
- Replies: 95
- Views: 55788
Re: Prove me wrong
The above process is wrong.Abdul Muntakim Rafi wrote:Bhaiya, we can't define $x/0$ where x is not equal to 0.
but we can define $0/0$
The above process proves that...
- Sat Dec 10, 2011 2:35 am
- Forum: Higher Secondary Level
- Topic: Prove me wrong
- Replies: 95
- Views: 55788
Re: Prove me wrong
I agree with Masum bhai. $a/b=c$ $a=b c$ Now if you take a and b to be 0 then Then your first line $a/b$ is undefined (not undetermined). The word undetermined has a very specific meaning; it means something is definable, but cannot determined. You cannot define something else like $a/b$ where $b \...
- Fri Dec 09, 2011 4:36 pm
- Forum: Higher Secondary Level
- Topic: Prove me wrong
- Replies: 95
- Views: 55788
Re: Prove me wrong
Actually it is undefined. Division is defined as multiplication by inverse, and there is no multiplicative inverse of zero. So division by zero is undefined.