## Search found 1175 matches

- Mon Oct 20, 2014 9:08 am
- Forum: Algebra
- Topic: (Angle)^(Side)[Inequality]
- Replies:
**7** - Views:
**3494**

### Re: (Angle)^(Side)[Inequality]

$\log$ - Chebyshev - Jensen - Sin law - Jensen - Exponent

- Fri Oct 17, 2014 7:30 pm
- Forum: Higher Secondary Level
- Topic: power and factorial
- Replies:
**7** - Views:
**4258**

### Re: power and factorial

Sorry, it was a typo. I meant to say NT, corrected now.

- Fri Oct 17, 2014 8:37 am
- Forum: Higher Secondary Level
- Topic: power and factorial
- Replies:
**7** - Views:
**4258**

### Re: power and factorial

Are you sure it is secondary level? This is BdMO forum, not any IMO specific forum; so I think it is better if you move it to at least Higher Secondary level or Olympiad Level Number Theory.

- Tue Oct 14, 2014 10:38 am
- Forum: International Mathematical Olympiad (IMO)
- Topic: IMO 2002 A1
- Replies:
**3** - Views:
**2131**

### Re: FE

IMO Shortlist 2002 Algebra 1

Hint:

Prove that $f$ is surjective.

Use $f^{-1}(0)$

Hint:

Prove that $f$ is surjective.

Use $f^{-1}(0)$

- Mon Oct 13, 2014 9:01 am
- Forum: Combinatorics
- Topic: Solution to a Non-Linear Recurrence
- Replies:
**4** - Views:
**2629**

### Re: Solution to a Non-Linear Recurrence

Can you provide the problem-specific values? Or is this purely a product of your thought?

- Thu Oct 09, 2014 2:10 pm
- Forum: Number Theory
- Topic: A very intuitive problem
- Replies:
**1** - Views:
**1525**

### A very intuitive problem

Prove that there are 100 natural number $a_1 < a_2 < ... < a_{99} < a_{100}$ $( a_i < 10^6 )$ such that $A , A+A , 2A , A+2A , 2A + 2A$ are five disjoint sets. $A = \{a_1 , a_2 ,... , a_{99} ,a_{100}\}$ $2A = \{2a_i \vert 1\leq i\leq 100 \}$ $A+A = \{a_i + a_j \vert 1\leq i<j\leq 100\}$ $A + 2A = \{...

- Sun Oct 05, 2014 7:21 pm
- Forum: Higher Secondary Level
- Topic: Eligibility for participation in BdMO/IMO
- Replies:
**8** - Views:
**4625**

### Re: Eligibility for participation in BdMO/IMO

But (there is always a but), BdMO rules are different. Every year the IMO candidates who get in various US universities are not officially enrolled till September, but are still considered ineligible for the IMO. So, just because someone is eligible for IMO doesn't mean he is eligible for BdMO. The ...

### Re: Confusion

Well, you can express that as $2ab = \dfrac{(a+b)^2-(a-b)^2}2$.

Also, welcome to BdMO Online Forum. Please see forum guides and rules here http://www.matholympiad.org.bd/forum/vi ... p?f=25&t=6 and "How to write LaTeX" here http://www.matholympiad.org.bd/forum/vi ... p?f=25&t=2 .

Also, welcome to BdMO Online Forum. Please see forum guides and rules here http://www.matholympiad.org.bd/forum/vi ... p?f=25&t=6 and "How to write LaTeX" here http://www.matholympiad.org.bd/forum/vi ... p?f=25&t=2 .

### Re: Confusion

Can you clarify what you're asking about a little more?

- Fri Oct 03, 2014 11:09 am
- Forum: Number Theory
- Topic: $a\equiv b$ whenever $F(a)\equiv F(b) (mod p)$
- Replies:
**8** - Views:
**3516**

### Re: $a\equiv b$ whenever $F(a)\equiv F(b) (mod p)$

Well, as I have SEEN, anything but established tools (double-derivatives for convexity) is looked down upon. Also, this type of cases (integration with integer parameters) can cause problems. For example, in this case, you need to define at least one other function, because 1. $\textbf{Differentiati...