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- Wed Jan 30, 2019 12:10 pm
- Forum: Asian Pacific Math Olympiad (APMO)
- Topic: APMO 2011 Problem 1
- Replies: 1
- Views: 9707
- Fri Dec 01, 2017 9:29 pm
- Forum: Geometry
- Topic: Geometry Marathon : Season 3
- Replies: 146
- Views: 192590
Re: Geometry Marathon : Season 3
A probelm is posted twice. So, actually this is the number 50. Problem 50: Let the incircle touches side $BC$ of a triangle $\triangle ABC$ at point $D$. Let $H$ be the orthocenter of $\triangle ABC$ and $M$ be the midpoint of segment $AH$. Let $E$ be a point on $AD$ so that $HE \perp AD$. Let $ME \...
- Mon Nov 20, 2017 12:32 pm
- Forum: Geometry
- Topic: Geometry Marathon : Season 3
- Replies: 146
- Views: 192590
Re: Geometry Marathon : Season 3
Problem 47: Let $ABCD$ be a cyclic quadrilateral. $AB$ intersects $DC$ at $E$. $AD$ intersects $BC$ at $F$. Let $M, N, P$ are midpoints of $BD, AC, EF$ respectively. Prove that $PN.PM=PE^2$
- Tue Oct 31, 2017 12:01 am
- Forum: Geometry
- Topic: Geometry Marathon : Season 3
- Replies: 146
- Views: 192590
Re: Geometry Marathon : Season 3
$\text{Problem 45}$ Let $ABC$ be a triangle with orthocentre $H$ and circumcircle $\omega$ centered at $O$. Let $M_a,M_b,M_c$ be the midpoints of $BC,CA,AB$. Lines $AM_a,BM_b,CM_c$ meet $\omega$ again at $P_a,P_b,P_c$. Rays $M_aH,M_bH,M_cH$ intersect $\omega$ at $Q_a,Q_b,Q_c$. Prove that $P_aQ_a,P_...
- Tue Sep 05, 2017 12:25 am
- Forum: Algebra
- Topic: Sequence and divisibility
- Replies: 2
- Views: 8450
Re: Sequence and divisibility
For the sake of the contradiction, let's assume that it does. Then, $a_1 \equiv a_1. a_2 \equiv a_1. a_2. a_3$ $\equiv........\equiv a_1. a_2......a_{k-2}. a_k$ $\equiv.....\equiv a_1. a_k \equiv a_k \pmod n$. So, $n$ divides $ |a_1 - a_k|$. But $0 < |a_1 - a_k| < n$, which is a contradiction. So, $...
- Wed Mar 29, 2017 7:28 pm
- Forum: National Math Camp
- Topic: The Gonit IshChool Project - Beta
- Replies: 28
- Views: 44595
Re: The Gonit IshChool Project - Beta
Name you'd like to be called: Tanmoy
Course you want to learn: Functional Equations and Number Theory Problem solving.
Preferred methods of communication (Forum, Messenger, Telegram, etc.):Telegram.
Do you want to take lessons through PMs or Public?: Public
Course you want to learn: Functional Equations and Number Theory Problem solving.
Preferred methods of communication (Forum, Messenger, Telegram, etc.):Telegram.
Do you want to take lessons through PMs or Public?: Public
- Fri Feb 24, 2017 9:21 pm
- Forum: Combinatorics
- Topic: Combi Marathon
- Replies: 48
- Views: 44668
Re: Combi Marathon
$\text {Problem 8}$ We have $\dfrac {n(n+1)} {2}$ stones in $k$ piles. In each move we take one stone from each pile and form a new pile with these stones (if a pile has only one stone, after that stone is removed the pile vanishes). Show that regardless of the initial configuration, we always end u...
- Fri Feb 24, 2017 5:09 pm
- Forum: International Mathematical Olympiad (IMO)
- Topic: IMO Marathon
- Replies: 184
- Views: 114647
Re: IMO Marathon
$\text{Problem 55}$
Let $n$ be a positive integer and let $(a_1,a_2,\ldots ,a_{2n})$ be a permutation of $1,2,\ldots ,2n$ such that the numbers $|a_{i+1}-a_i|$ are pairwise distinct for $i=1,\ldots ,2n-1$.
Prove that $\{a_2,a_4,\ldots ,a_{2n}\}=\{1,2,\ldots ,n\}$ if and only if $a_1-a_{2n}=n$.
Let $n$ be a positive integer and let $(a_1,a_2,\ldots ,a_{2n})$ be a permutation of $1,2,\ldots ,2n$ such that the numbers $|a_{i+1}-a_i|$ are pairwise distinct for $i=1,\ldots ,2n-1$.
Prove that $\{a_2,a_4,\ldots ,a_{2n}\}=\{1,2,\ldots ,n\}$ if and only if $a_1-a_{2n}=n$.
- Fri Feb 24, 2017 4:27 pm
- Forum: Combinatorics
- Topic: Combi Marathon
- Replies: 48
- Views: 44668
Re: Combi Marathon
$\text{Problem 7}$ Elmo is drawing with colored chalk on a sidewalk outside. He first marks a set $S$ of $n>1$ collinear points. Then, for every unordered pair of points $\{X,Y\}$ in $S$, Elmo draws the circle with diameter $XY$ so that each pair of circles which intersect at two distinct points ar...
- Fri Feb 24, 2017 1:25 pm
- Forum: International Mathematical Olympiad (IMO)
- Topic: IMO Marathon
- Replies: 184
- Views: 114647
Re: IMO Marathon
$\text{Problem 54}$ The following operation is allowed on a finite graph: choose any cycle of length $4$ (if one exists), choose an arbitrary edge in that cycle, and delete this edge from the graph. For a fixed integer $n \ge 4$, find the least number of edges of a graph that can be obtained by rep...