Search found 33 matches
- Sun Jan 06, 2013 2:08 pm
- Forum: Secondary Level
- Topic: Multiple of 5
- Replies: 8
- Views: 4985
Re: Multiple of 5
$\frac{99999999-9999999}{10}\cdot2=18000000$
- Tue Jan 01, 2013 12:41 am
- Forum: Social Lounge
- Topic: Happy New year 2013
- Replies: 2
- Views: 2937
Re: Happy New year 2013
শুভ হোক একুশতম অশুভ বছর!
- Sat Dec 29, 2012 10:51 pm
- Forum: Site Support
- Topic: About: Youtube and proxies
- Replies: 7
- Views: 7160
Re: Experiment of Galileo
কি আশ্চর্য! আমার ইউটিউব দেখতে কোন সমস্যা হয় না! কেন কে জানে!(বোধহয় সরকারী জিনিস ব্যবহার করি ঐজন্যে!) @Prosenjit, মাঝে যখন ফেসবুক বন্ধ করসিল, তখন আমি "Freegate" নামের একটা সফটওয়্যার ব্যবহার করসিলাম(এইটা সম্ভবত শুধু IE তে কাজ করে)। freegate গুগল করলেই পাবা। অনেকে "Tor"(browser) ব্যবহার করে, তবে শুন...
- Sat Dec 29, 2012 10:41 pm
- Forum: International Olympiad in Informatics (IOI)
- Topic: Regional BdOI 2013 Questions
- Replies: 11
- Views: 18412
Re: Regional BdOI 2013 Questions
Hint:Illusory Time wrote:Question 2:(i)
Propose a general method to find the final value of V for any binary number B. How it should be solved?
- Fri Dec 28, 2012 10:22 pm
- Forum: International Olympiad in Informatics (IOI)
- Topic: Solving regional BdOI Dhaka-2013
- Replies: 7
- Views: 14056
Re: Solving regional BIOC Dhaka-2013
there was same question in all divisions, and hey... it's BdOI, not BIOC(it actually means Bangladesh Informatics Olympiad Committee) এক জন যদি একটা করে পোস্ট করে তাহলেই তো দশটা হয়ে যায়... i'm posting number 10(oh yeah! i liked it!) $10.$ $n$ pigeonholes are kept side by side in a row. you want to...
- Fri Dec 28, 2012 10:11 pm
- Forum: Introductions
- Topic: আবার দেখা!
- Replies: 9
- Views: 8151
Re: আবার দেখা!
এইটা একটা ধাঁধা! আমার নাম লুকায়ে আছে এর মাঝে!nafistiham wrote:সব নামেরই অর্থ পাওয়া গেল, কিন্তু kfoozminus কি জিনিস ?
- Fri Dec 28, 2012 9:32 pm
- Forum: Combinatorics
- Topic: Probability in a football game
- Replies: 11
- Views: 8669
Re: Probability in a football game
thanks for finding the bug... this was so annoying me...
hey, maybe you can look into this too viewtopic.php?f=28&t=2216
i'm not sure about the answer, and looks like nobody's interested in football!
hey, maybe you can look into this too viewtopic.php?f=28&t=2216
i'm not sure about the answer, and looks like nobody's interested in football!
- Fri Dec 28, 2012 7:57 pm
- Forum: Combinatorics
- Topic: Probability In A Five-Team Tournament
- Replies: 3
- Views: 3535
Re: Probability In A Five-Team Tournament
yeah, you're right... editedShihab wrote:You made a little mistake. In the third case, (which produce one undefeated team and one winless team) i think you have to permute the two teams. That means there are 5P2 such choices not 5C2.
- Thu Dec 27, 2012 5:43 pm
- Forum: Combinatorics
- Topic: Probability In A Five-Team Tournament
- Replies: 3
- Views: 3535
Re: Probability In A Five-Team Tournament
$\frac{17}{32}$ there will be total $^5C_2=10$ matches and there can be $2^{10}$ results. let's count in how many cases there will be an undefeated team and/or winless team. there can't be more than one undefeated team or winless team in a single case. so, number of cases in which one team wins all ...
- Mon Dec 24, 2012 4:36 pm
- Forum: Combinatorics
- Topic: Probabiity in Football game.
- Replies: 4
- Views: 4223
Re: Probabiity in Football game.
67/153 :) :) how did you get it? i've got $\frac{63}{703}$ :? in each part, at most $2$ goals can be made. so, at most $36$ goals can be made in $18$ parts. after the end of the game, $0$ goal or $1$ goal or $2$ goals or $3$ goals... or $36$ goals can be made totally. $0$ goal can be made in $1$ wa...