2008 - Higher Secondary (integration)

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Zzzz
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2008 - Higher Secondary (integration)

Unread post by Zzzz » Wed Dec 29, 2010 12:16 pm

$f(x)$ is a complicated nonlinear function. $f(x)+f(1-x)=1$. Evaluate $\int_0^1f(x)dx$.

Complicated nonlinear function কী?

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tanvirab
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Re: 2008 - Higher Secondary (integration)

Unread post by tanvirab » Wed Dec 29, 2010 3:26 pm

non-linear means it's graph is not a straight line. Complicated means it's complicated. :)

That information is irrelevant.

The important information is the given equation. Divide the interval of integration into two halves.

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Zzzz
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Re: 2008 - Higher Secondary (integration)

Unread post by Zzzz » Wed Dec 29, 2010 3:53 pm

Thanks .. :)
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Masum
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Re: 2008 - Higher Secondary (integration)

Unread post by Masum » Thu Dec 30, 2010 9:44 pm

I don't know how to type integration.So let's agree to denote it as sum only
$\int_0^a f(x)dx=\int_0^a f(a-x)dx$,so it is $\frac 1 2$(set $a=1$ $\text {and use}$ $ f(x)+f(1-x)=1$)
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Avik Roy
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Re: 2008 - Higher Secondary (integration)

Unread post by Avik Roy » Sat Jan 01, 2011 10:09 pm

Masum, you can get the code to write the correct latex code by double clicking on the integration in Zubayer's post. I hope you can now edit your code
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Masum
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Re: 2008 - Higher Secondary (integration)

Unread post by Masum » Sun Jan 02, 2011 1:16 pm

But the time is over.help-mods
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