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$f(x)$ is a complicated nonlinear function. $f(x)+f(1-x)=1$. Evaluate $\int_0^1f(x)dx$.

Complicated nonlinear function কী?

সমাধানটাও কেউ একটু দিয়েন...

non-linear means it's graph is not a straight line. Complicated means it's complicated.

That information is irrelevant.

The important information is the given equation. Divide the interval of integration into two halves.

Thanks ..

I don't know how to type integration.So let's agree to denote it as sum only
$\int_0^a f(x)dx=\int_0^a f(a-x)dx$,so it is $\frac 1 2$(set $a=1$ $\text {and use}$ $ f(x)+f(1-x)=1$)

Masum, you can get the code to write the correct latex code by double clicking on the integration in Zubayer's post. I hope you can now edit your code

But the time is over.help-mods