## BdMO National 2013: Secondary 4

Discussion on Bangladesh Mathematical Olympiad (BdMO) National
BdMO
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Joined: Tue Jan 18, 2011 1:31 pm

### BdMO National 2013: Secondary 4

$ABCD$ is a quadrilateral where $\angle B=\angle D=90^{\circ}$. $E$ and $F$ are two points on $BD$ such that $AE$ is perpendicular to $BD$ and $CF||AE$. Prove that, $DE=BF$.

Tahmid
Posts: 110
Joined: Wed Mar 20, 2013 10:50 pm

......proved...