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Let $\triangle ABC $ be an acute angled triangle with $\angle C=60^{\circ}$.Perpendicular $AA_1$ & $BB_1$ are drawn from point $A$ and $B$ to the sides $BC$ & $AC$ respectively.Let $M$ be the midpoint of $AB$.What is the value of $\dfrac {\angle A_1MB_1}{\angle A_1CB_1}$?

Hint Answer Figure