BDMO National Junior 2018/2
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nahin munkar
- Posts:81
- Joined:Mon Aug 17, 2015 6:51 pm
- Location:banasree,dhaka
If the average of first $n$ positive integers is $2018$, then find the value of n ?
# Mathematicians stand on each other's shoulders. ~ Carl Friedrich Gauss
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samiul_samin
- Posts:1007
- Joined:Sat Dec 09, 2017 1:32 pm
Re: BDMO National Junior 2018/2
Sum of first n positive integers is $n×(n+1)/2$
So the average of first n positive integers is $(n+1)/2$
If $(n+1)/2=2018 $ then $n=4035$
So the average of first n positive integers is $(n+1)/2$
If $(n+1)/2=2018 $ then $n=4035$