BDMO National Junior 2018/4
- nahin munkar
- Posts:81
- Joined:Mon Aug 17, 2015 6:51 pm
- Location:banasree,dhaka
The squares of three positive numbers add up to $2018$. The biggest of these three numbers is the sum of the smaller two. If the difference between the smaller two numbers is $2$, what is the difference between the cubes of the smaller two numbers?
# Mathematicians stand on each other's shoulders. ~ Carl Friedrich Gauss
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Re: BDMO National Junior 2018/4
Suppose the biggest number is $c$
The second highest is $a$
And smallest is $b$
Now
$a^2+b^2+c^2=2018$
$a^2+b^2+(a+b)^2=2018$
$a^2+b^2+ab=1009$
$(a-b)(a^2+ab+b^2)=2×1009$
$a^3-b^3=2018$
Given that,
$a+b=c$
$a-b=2$
The second highest is $a$
And smallest is $b$
Now
$a^2+b^2+c^2=2018$
$a^2+b^2+(a+b)^2=2018$
$a^2+b^2+ab=1009$
$(a-b)(a^2+ab+b^2)=2×1009$
$a^3-b^3=2018$
Given that,
$a+b=c$
$a-b=2$