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ABC is a triangle. D is a random point on BC and F is a random point on AC . BF and AD intersect at point E . AE = ED. BD = 2CD. find the area of BDE+AEF. Area of triangle ABC IS 5 sq units.

can anybody give me a solve ?

Safwan wrote: ↑

Mon Feb 04, 2019 10:24 am

ABC is a triangle. $D$ is a random point on $BC$ and $F$ is a random point on $AC$ . $BF$ and $AD$ intersect at point$E$ . $AE = ED$. $BD = 2CD$. find the area of $[BDE]+[AEF]$.

Is given information is enough to find the area?I am not understanding because no measurement of sides or angles is given. :?:Or Am I getting the question wrong?

SORRY ABC=5 sq. units