BdMO National Junior 2010/4
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- Posts:1007
- Joined:Sat Dec 09, 2017 1:32 pm
Find the smallest number,divisible by $13$ ,such that the remainder is $1$ when divided by $4,6$ or $9$.
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- Posts:1007
- Joined:Sat Dec 09, 2017 1:32 pm
Re: BdMO National Junior 2010/4
Answer:$\fbox {325}$
Solution:
LCM$(4,6,9)=36$
So the number must be $36n+1$
and the number can also be presented as $13m$
That means $36n+1=13m$
Where $n$,$m$ both are integers.
Pluuging the value of $n$ from $1$ to $9$ .
We will get our desired answer $325$.
Solution:
LCM$(4,6,9)=36$
So the number must be $36n+1$
and the number can also be presented as $13m$
That means $36n+1=13m$
Where $n$,$m$ both are integers.
Pluuging the value of $n$ from $1$ to $9$ .
We will get our desired answer $325$.