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Posted: **Sun Feb 06, 2011 10:13 pm**

Problem 1:

: Image-problem 1.JPG (6.91KiB)Viewed 2574 times

In the figure $AB=8,\ BC=7$ and $CA=6.\ \Delta PAB$ is similar to $\Delta PCA$. What is $PC$?

Posted: **Mon Jan 23, 2012 3:41 pm**

here,
\[\frac{PC}{PA}=\frac{AC}{AB}=\frac{PA}{PB}\]
suppose, $PC=x$ and $PA=y$
so,
\[\frac{x}{y}=\frac{3}{4}=\frac{y}{7+x}\]
from which we get $2$ equations,
by solving them we can get $PC$

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