Problem 2:
$WZ$ is the diameter of circle with center $O$. $OY=5$, arc $XY$ creates angle $60^{\circ}$ at the center. If $\angle ZYO=60^{\circ}$, then $XY=?$.
BdMO National Higher Secondary 2007/2
Re: BdMO National Higher Secondary 2007/2
I think X,Y are on the circumference.
Then OX=OY. So it's a equilateral triangle.
XY=5
Then OX=OY. So it's a equilateral triangle.
XY=5
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Re: BdMO National Higher Secondary 2007/2
If I am not wrong, then the solution is:
Between triangle XOY and OYZ, XO=OY=OZ=5 (radius of the same circle) and <XOY=<OYZ=60 degree.
So, triangle XOY =~ OYZ. So, XY=OZ=5.
Between triangle XOY and OYZ, XO=OY=OZ=5 (radius of the same circle) and <XOY=<OYZ=60 degree.
So, triangle XOY =~ OYZ. So, XY=OZ=5.