BdMO National Higher Secondary 2008/10

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Moon
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BdMO National Higher Secondary 2008/10

Unread post by Moon » Sun Feb 06, 2011 11:20 pm

Problem 10:
A quadrilateral $ABCD$ with $\angle BAD + \angle ADC > 180^\circ$ circumscribes a circle of center $I$. A line through $I$ meets $AB$ and $CD$ at points $X$ and $Y$ respectively. If $IX = IY$ then what is
\[ \frac{AX\cdot DY}{BX \cdot CY}\]
"Inspiration is needed in geometry, just as much as in poetry." -- Aleksandr Pushkin

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bristy1588
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Re: BdMO National Higher Secondary 2008/10

Unread post by bristy1588 » Sat Jan 14, 2012 9:56 pm

Hints anyone?
Bristy Sikder

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Tahmid Hasan
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Re: BdMO National Higher Secondary 2008/10

Unread post by Tahmid Hasan » Sun Jan 15, 2012 10:07 am

try to prove $MX=NY$,where $M,N$ denote the tangent points on $AB,CD$ respectively.
বড় ভালবাসি তোমায়,মা

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