BdMO National Higher Secondary 2009/7

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Moon
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BdMO National Higher Secondary 2009/7

Unread post by Moon » Sun Feb 06, 2011 11:34 pm

Problem 7:
How many positive prime numbers can be written as an alternating sequence of $1$'s and $0$'s where the first and last digit is $1$?
An alternating sequence of $1$'s and $0$'s is for example: $N = 1010101$ and has the property that $99N = 99999999$.
"Inspiration is needed in geometry, just as much as in poetry." -- Aleksandr Pushkin

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Labib
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Re: BdMO National Higher Secondary 2009/7

Unread post by Labib » Mon Feb 07, 2011 11:41 pm

If the number has even number of 1's, it will be dividable by 101. But could be the next steps??
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Mehfuj Zahir
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Re: BdMO National Higher Secondary 2009/7

Unread post by Mehfuj Zahir » Tue Feb 08, 2011 12:17 am

prove that 1010101.......is a geometric sequence.example10101=10000+100+1. now try to prove that this type of sequence has factor.so you will get one prime number is 101

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Re: BdMO National Higher Secondary 2009/7

Unread post by Labib » Wed Feb 16, 2011 10:55 pm

thank you for the suggestion.
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Re: BdMO National Higher Secondary 2009/7

Unread post by Masum » Thu Mar 03, 2011 10:50 am

It is $10^{2k-2}+...+10^2+1=\frac {10^{2k}-1} {99}$
So if $k>1$ then let $k=2^rs,s$ odd and note that $x^{pq}-1$ is divisible by $(x^p-1)(x^q-1)$
One one thing is neutral in the universe, that is $0$.

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