Problem 8:
The region $A$ is bounded by the $x$-axis, the line $y=\frac {x}{2}$ and the ellipse $\frac {x^2}{9}+y^2=1$. The region $B$ is bounded by the $y$-axis, the line $y = mx$ and the ellipse $y=\frac {x}{2}$ and the ellipse $\frac {x^2}{9}+y^2=1$. Find $m$ such that area of region $A$ is the equal to the area of region $B$.
BdMO National Higher Secondary 2009/8
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samiul_samin
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Re: BdMO National Higher Secondary 2009/8
Problem sourceMoon wrote: ↑Sun Feb 06, 2011 11:34 pmProblem 8:
The region $A$ is bounded by the $x$-axis, the line $y=\frac {x}{2}$ and the ellipse $\frac {x^2}{9}+y^2=1$. The region $B$ is bounded by the $y$-axis, the line $y = mx$ and the ellipse $y=\frac {x}{2}$ and the ellipse $\frac {x^2}{9}+y^2=1$. Find $m$ such that area of region $A$ is the equal to the area of region $B$.
Putnum 1994 P2